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2 years ago

6. A. If 4.50 mols of ethane, C2H6, undergoes combustion according to the unbalanced equation

Chemistry

1 answer:

uranmaximum [27]2 years ago

6 0

Answer:

for one mole of C2H6 there are 7/2 mole of O2 required. so for4. 50 moles you require 4.50 x 7/2 = 15.75 moles of O2.

Explanation:

i hope it's helpful

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What is the solubility in moles/liter for silver chloride at 25 oC given a Ksp value of 1.6 x 10-10. Write using scientific nota

trapecia [35]

Answer:

Explanation:

AgCl ⇄ Ag⁺ + Cl⁻

m m m

If x mole of AgCl be dissolved in one litre .

[ Ag⁺ ] [ Cl⁻ ] = 1.6 x 10⁻¹⁰

m² = 1.6 x 10⁻¹⁰

m = 1.26 x 10⁻⁵ moles

So solubility of AgCl is 1.26 x 10⁻⁵ moles / L

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3 years ago

What is the pressure in a gas container that is connected to an open-end U-tube manometer if the pressure of the atmosphere is 7

Whitepunk [10]

Answer:

The pressure in the gas is 656mmHg

Explanation:

In calculating the pressure of the gas;

step 1: convert the height of the mercury arm to mmHg

9.60cm = 96.0 mmHg

step 2: convert 752 torr to mmHg

I torr is 1 mmHg

752 torr = 752mmHg

Step 3: since the level of mercury in the container is higher than the level of mercury exposed to the atmosphere, we substrate the values to obtain our pressure.

So, 752mmHg - 96mmHg = 656mmHg

The pressure in the gas container is therefore 656mmHg.

N. B : if the mercury arm is in lower position, you add.

5 0

3 years ago

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Margarita [4]

Answer:

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3 years ago

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An oxide of aluminum contains 0.545 g of Al and 0.485 g of O. Find the empirical formula

uysha [10]

Answer:

The answer is: Al2O3

Explanation:

The data they give us is:

0.545 gr Al

0.485 gr O.

To find the empirical formula without knowing the grams of the compound, we find it per mole:

0.545 g Al * 1 mol Al / 27 g Al = 0.02 mol Al

0.485 g O * 1 mol O / 16 g O = 0.03 mol O

Then we must divide the results obtained by the lowest result, which in this case is 0.02:

0.02 mol Al / 0.02 = 1 Al

0.03 mol O / 0.02 = 1.5 O

Since both numbers have to give an integer, multiply by 2 until both remain integers:

1Al * 2 = 2Al

1.5O * 2 = 3O

Now the answer is given correctly:

Al2O3

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2 years ago

Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?

xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed methyl vinyl ketone.

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when formaldehyde and acetone then react with each other then it will be formed methyl vinyl ketone.

It can be written as

$CH_{2} O + CH_{3} COCH_{3}$ → $HOCH_{2} -CH_{2} -CO-CH_{3}$

When it will be heated then it gives methyl vinyl ketones.

$HOCH_{2} -CH_{2} -CO-CH_{3}$ → $CH_{2} =CH-CO-CH_{3}$

So, the pair of reactants will be formaldehyde and acetone

To know more about aldol condensation

brainly.com/question/9415260

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6 0

1 year ago