What's the big M? Molecular weight or mol?
Answer:
Convergent, divergent, transform
Explanation:
Convergent- tectonic plates move towards one another
Divergent- they move away from each other, or in other directions
Transform- tectonic plates slide past/against each other
Water can only be the solvent, never the solute is the statement about a solution that is correct.
- The solute is the substance that, in general, is found in less quantity and that dissolves in the mixture.
- The solvent, on the other hand, is the substance that usually appears in greater quantity and where the solute dissolves.
- The most usual thing is that the solvent is the substance that establishes the physical state of the solution.
- Water is considered a universal solvent, since it is the liquid that dissolves the most substances, a quality linked to its status as a “polar molecule”, this is due to its ability to form hydrogen bonds with other substances.
Solubility depends on the properties of a solvent that allow it to interact with a solute in a stronger way than the solvent particles do with each other.
In particular, the polar character of water makes it an excellent solvent for polar and ionic solutes, which are called hydrophilic.
Therefore, we can conclude that water can only be the solvent, never the solute is the statement about a solution that is correct.
Learn more here: brainly.com/question/2835889
Answer:
333.7 g.
Explanation:
- The depression in freezing point of water (ΔTf) due to adding a solute to it is given by: <em>ΔTf = Kf.m.</em>
Where, ΔTf is the depression in water freezing point (ΔTf = 20.0°C).
Kf is the molal freezing point depression constant of the solvent (Kf = 1.86 °C/m).
m is the molality of the solution.
<em>∴ m = ΔTf/Kf</em> = (20.0°C)/(1.86 °C/m) = <em>10.75 m.</em>
molaity (m) is the no. of moles of solute per kg of the solvent.
∵ m = (no. of moles of antifreeze C₂H₄(OH)₂)/(mass of water (kg))
∴ no. of moles of antifreeze C₂H₄(OH)₂ = (m)(mass of water (kg)) = (10.75 m)(0.5 kg) = 5.376 mol.
∵ no. of moles = mass/molar mass.
<em>∴ mass of antifreeze C₂H₄(OH)₂ = no. of moles x molar mass </em>= (5.376 mol)(62.07 g/mol) =<em> 333.7 g.</em>
