Answer:
W = 181.26 J
Explanation:
Given that,
The force acting on the cart, F = 20 N
It is at an angle of 25 degrees above the horizontal to move a crate a distance of 10m across the floor.
We need to find work done by the student. The work done by the student is given by :
So, the required work done is 181.26 J.
Answer:
a) 30.20 m/s
b) 12.91 m/s
Explanation:
Mass of squirrel = 575 g = m
Drag coefficient = 0.70 = C
Density of air = 1.21 kg/m³ = ρ
frontal surface area = 0.0146 m² = A
Height the squirrel falls = 8.5 m = h
a) Drag force
This force will oppose gravity
∴ Terminal velocity is 30.20 m/s
b) Neglecting drag force we get
∴ Velocity of a 56 kg person falling that distance, assuming no drag contribution is 12.91 m/s
it is a surface layered infection that is commonly found on soft tissue or within the nasal cavity.
Acceleration=change in velocity divided by change in time or
we are given that it goes from 5m/s to 15m/s
in this case,
and the change in time or
is 1 second because this change occurs over a period of 1 second
so the acceleration is
the acceleration is
What are your answers?Or is this a short answer?