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Vesna [10]
3 years ago
5

What is the torque about the center of the sun due to the gravitational force of attraction of the sun on the planet?

Physics
1 answer:
Anon25 [30]3 years ago
3 0
Torque, moment, or moment of force is the tendency of a force to rotate an object around an axis,fulcrum, or pivot. Just as a force is a push or a pull, a torque can be thought of as a twist to an object. Mathematically, torque is defined as the cross product of the vector by which the force's application point is offset relative to the fixed suspension point (distance vector) and the force vector, which tends to produce rotational motion. So torque about the center of the sun due to the gravitational force of attraction of the sun on the planet = (Gxm1xm2 / r^2). r sin(theta) = Gxm1xm2 /r^2). r sin0° = 0
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Answer:

Explanation:

The attraction weakens. Two objects that are farther apart are not drawn together as strongly as if they were close together.

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A person drives a car around a circular cloverleaf with a radius of 77 m at a uniform speed of 10 m/s. What is the acceleration
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A narrow beam of light from a laser travels through air (n = 1.00) and strikes the surface of the water (n = 1.33) in a lake at
Natalka [10]

Answer:

A) d = 11.8m

B) d = 4.293 m

Explanation:

A) We are told that the angle of incidence;θ_i = 70°.

Now, if refraction doesn't occur, the angle of the light continues to be 70° in the water relative to the normal. Thus;

tan 70° = d/4.3m

Where d is the distance from point B at which the laser beam would strike the lakebottom.

So,d = 4.3*tan70

d = 11.8m

B) Since the light is moving from air (n1=1.00) to water (n2=1.33), we can use Snell's law to find the angle of refraction(θ_r)

So,

n1*sinθ_i = n2*sinθ_r

Thus; sinθ_r = (n1*sinθ_i)/n2

sinθ_r = (1 * sin70)/1.33

sinθ_r = 0.7065

θ_r = sin^(-1)0.7065

θ_r = 44.95°

Thus; xonsidering refraction, distance from point B at which the laser beam strikes the lake-bottom is calculated from;

d = 4.3 tan44.95

d = 4.293 m

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roller coaster system is greatest at the bottom of the largest downhill slope on the track typically at the bottom of the lift Hill

so at the bottom

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