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Degger [83]
3 years ago
14

Melting Point of Substances

Physics
2 answers:
ivanzaharov [21]3 years ago
7 0
116 and 136.5 i think? Hope it helps

frez [133]3 years ago
5 0
<span>(kg) Melting Point of Tin

</span>
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A conducting loop of radius 1.50 cm and resistance 8 × 10−6Ω is perpendicular to a uniform magnetic field of magnitude 23.0 × 10
Anika [276]

To solve this problem it is necessary to apply the concepts related to electromotive force or induced voltage.

By definition we know that the induced emf in the loop is equal to the negative of the change in the magnetic field, that is,

\epsilon = -A \times \frac{\Delta B}{\Delta t}

\epsilon = -A \times (\frac{B_f-B_i}{t_f-t_i})

Where A is the area of the loop, B the magnetic field and t the time.

Replacing with our values we have that

\epsilon = -(\pi (1.5*10^{-2})^2)(\frac{0-23*10^{-6}}{7*10^{-3}-0})

\epsilon = 2.3225*10^{-6}V

Therefore the thermal energy produced is given by

E = P*t = \frac{\epsilon^2}{R}t

E = \frac{(2.3225*10^{-6})^2}{8*10^{-6}}*(7*10^{-3})

E = 4.719*10^{-9}J

The thermal energy produced in the loop is 4.719*10^{-9}J

4 0
3 years ago
The forces exerted on an object are shown.
damaskus [11]

The reaper watches. Satan watches. We all watch. As we fade. Into oblivion.

8 0
3 years ago
How do you explain the differences in the work along the plane and the work through the vertical height?
Elan Coil [88]
There’s no work along the plane, while work increases as the height increases

Another example,
When you’re picking up a box... that’s work
When you are walking WITH the box, no work
8 0
4 years ago
Need help ASAP!!!!!!!!!!!
andriy [413]

Answer:

The equation says that due to variation in temperature is

delt T = .59 m/s / C = 16 C * .59 m/s = 9.44 m/s

So v = 332 m/s + 9.44 m/s = 341 m/s (to three significant figures)

4 0
3 years ago
You are in a hot air balloon (yes, another balloon problem!) rising from the ground at a constant velocity of 2.00 m/s upward. t
Daniel [21]
If all you need is the initial speed of the cork, you can solve this using only two of your given:
2.00 m.s upward and 6.60 m.s horizontally.

If you take in consideration the movement of the cork, you know that it was both going up and forward at the same time, this means that it was moving at a diagonal direction. Now you can solve this by using the Pythagorean theorem where: 

c =  \sqrt{ a^{2} +  b^{2}  }

Why? Because the vertical and the horizontal motion creates a movement that is diagonal, which when put in a free-body diagram, creates a right triangle. 

Going back to your problem, when applying this, the diagonal of a right triangle is the hypotenuse, so this is what you are looking for. The horizontal and vertical motion will represent the other 2 sides of the triangle. 

Now let's put that into your formula:

c = \sqrt{ a^{2} + b^{2} }

Vi = \sqrt{ Vx^{2} + Vy^{2} }

Where: Vx is your horizontal velocity
             Vy is your vertical velocity
             Vi  is your initial velocity

Now let's put in your given:

Vi = \sqrt{ Vx^{2} + Vy^{2} }
Vi = \sqrt{ 6.60^2} + 2.00^{2} }
Vi = \sqrt{ 43.56 + 4.00 }
Vi = \sqrt{ 47.56 }
Vi = 6.8964 m/s

So your initial velocity is 6.8964 m/s or 6.90 m/s
5 0
4 years ago
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