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EleoNora [17]
3 years ago
12

A pure compound is found to be 40.0% carbon by mass, 6.73% hydrogen by mass, and 53.3% oxygen by mass. determine the empirical f

ormula of the compound. be sure to show your work.
Chemistry
1 answer:
ratelena [41]3 years ago
3 0
Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O

With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
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Describe two advantages and two disadvantages of building your 3D model with modeling clay. (5 points)
marishachu [46]

Answer:

A model or simulation is only as good as the rules used to create it. It is very difficult to create an entirely realistic model or simulation because the rules are based on research and past events. The main disadvantage of simulations is that they aren't the real thing.

Explanation:

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3 years ago
Compare the energy required to break the bonds of the reactants and the energy released when products form in an exorgonic react
const2013 [10]
When products form in an exergonic reaction, the <span>energy required to break bonds is less than the energy released from new bonds. This is usually given off as light. I hope this is the answer you are looking for. Looking forward to help you again. Have a great day ahead!</span>
7 0
3 years ago
Read 2 more answers
If 5.4 moles of Fe react with 4.7 moles of O2, what is the maximum amount of Fe2O3 (in moles) that can be produced? What is the
DIA [1.3K]

Answer:

2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Fe: 4 moles
  • O₂: 3 moles
  • Fe₂O3: 2 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

You can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe reacts with 3 moles of O₂, how much moles of Fe will be needed if 4.7 moles of O₂ react?

moles of Fe =\frac{4. moles of Fe*4.7 moles of O_{2}}{3 moles of O_{2} }

moles of O₂= 6.27

But 6.27 moles of Fe are not available, 5.4 moles are available. Since you have less moles than you need to react with 4.7 moles of O₂, iron Fe will be the limiting reagent.

So you can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, how many moles of Fe₂O₃ will be produced if 5.4 moles of Fe react?

moles of Fe_{2}O_{3}=\frac{5.4 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}

moles of Fe₂O₃= 2.7 moles

Then:

<u><em>2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.</em></u>

4 0
3 years ago
Identify the correct statement. A. It is not possible for two atoms to share more than two electrons. B. A covalent bond has a l
RSB [31]

Answer:

B. A covalent bond has a lower potential energy than the two separate atoms.

Explanation:

<em>Identify the correct statement. </em>

<em>A. It is not possible for two atoms to share more than two electrons.</em> FALSE. Atoms also can share 4 electrons (double bond) or 6 electrons (triple bond).

<em>B. A covalent bond has a lower potential energy than the two separate atoms.</em> TRUE.

<em>C. Single bonds are shorter than double bonds.</em> FALSE. Single bonds are longer than double bonds.

<em>D. A covalent bond is formed through the transfer of electrons from one atom to another.</em> FALSE. In covalent bonds, electrons are shared, not transferred from one atom to another.

<em>E. A pair of electrons involved in a covalent bond are sometimes referred to as lone pairs.</em> FALSE. Lone pairs are those that do not participate in a bond.

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Lunna [17]

Answer: here is a description of what they look like since I cannot see the diagram.

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I sure hope this helps!!!

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