P and S
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Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).
Hope this helps :)
<u>Answer:</u> The correct answer is 1.18 g.
<u>Explanation:</u>
We are given a chemical equation:
![C(S)+O2(g)\rightarrow CO_2(g)](https://tex.z-dn.net/?f=C%28S%29%2BO2%28g%29%5Crightarrow%20CO_2%28g%29)
We know that at STP conditions:
22.4L of volume is occupied by 1 mole of a gas.
So, 2.21L of carbon dioxide is occupied by =
of carbon dioxide gas.
By Stoichiometry of the above reaction:
1 mole of carbon dioxide gas is produced by 1 mole of carbon
So, 0.0986 moles of carbon dioxide is produced by =
of carbon.
Now, to calculate the mass of carbon, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Moles of carbon = 0.0986 mol
Molar mass of carbon = 12 g/mol
Putting values in above equation, we get:
![0.0986mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=1.18g](https://tex.z-dn.net/?f=0.0986mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20carbon%7D%7D%7B12g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20carbon%7D%3D1.18g)
Hence, the correct answer is 1.18 g.