Answer:
The correct answer:
8)- e)2, 2 dymetilpropane
9)- b) 2-chloropropane
10)- b) hydroxyl
See the explanation below, please.
Explanation:
In the cases of exercises 8 and 9:
Correspond to alkanes, having 3 carbons are named with the prefix prop and suffix anus. In 8 it has 2, 2 methyl groups in carbon and 9 in a 2-carbon chlorine group.
In the case of 10, it corresponds to a 3-carbon alcohol: suffix prop, and prefix ol: 2- propanol; in group 2 it has an OH group corresponding to alcohol (hydroxyl).
The frequency of this line of vanadium is 9.38 x10 ^14 Hz.
Emission spectrum shows how the electron of an atom goes or moves from a higher to a lower energy level.
Now The energy of a photon is given by
E = hc/λ
where
h = Plank's constant = 6.626 x 10⁻³⁴ J s
c = speed of light= 3 x 10⁸ m/s
λ = wavelength = 318.5 x 10⁻⁹ m
Solving
E = (6.626 x 10⁻³⁴ J s x 3 x 10⁸ m/s) / 318.5 x 10⁻⁹ m
E =6.2166 x10 ^-19 J
Also, we know that energy is related to frequency by the equation
E =hf
Where;
h = Planks's constant
f = frequency of photon
Making frequency subject of the formulae
f = E/h
f =6.2166 x10 ^-19 J/ 6.626 x 10⁻³⁴ J s
f = 9.38 x10 ^14 Hz
See similar question and solution here:brainly.com/question/24630281
The empirical formula is a formula obtained as the result of the quantitative analysis.
СH₃ is the empirical formula for C₂H₆
Answer:
I am really sorry but and I needed points urgently
Explanation:
Sorry sorry
Answer is: 4.02 <span>grams of water are required.
</span>Chemical reaction: BaH₂ + 2H₂O → Ba(OH)₂ + 2H₂.
Ideal gas law: p·V =
n·R·T.<span>
p = 755 mm Hg </span>÷ 760.0 mmHg / atm = 0.993<span> atm.
T = 25 + 273.15 = 298.15 K.
V(H</span>₂) <span>= 5.50 L.
R = 0,08206 L·atm/mol·K.
n(H</span>₂)
= <span>0.993 atm · 5.5 L ÷ 0,08206 L·atm/mol·K · 298.15 K.
n(H</span>₂)
= 0.223 mol.<span>
From chemical reaction: n(H</span>₂O) : n(H₂) = 1 : 1.<span>
n</span>(H₂O) = 0.223 mol.<span>
m</span>(H₂O) =
0.223 mol · 18 g/mol.<span>
m</span>(H₂O) =
4.02 g.
