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dem82 [27]
4 years ago
7

For a futuristic spacecraft, a solar sail was used as a means of propulsion. Assume the spacecraft had a mass of 360 kg, the sai

l area (perpendicular to the Sun) was 1 million square meters, and the spacecraft was 0.5 AU (astronomical units) from the Sun. Remember than 1 AU is the Earth to Sun distance. Assume the reflectivity of the sail was 1.0. What is the acceleration (in m/s2) of the spacecraft away from the Sun?
Physics
1 answer:
IRISSAK [1]4 years ago
7 0

Answer:

a = 5.037 10⁻²  m / s²

Explanation:

For this exercise we will use the concept of radiation pressure for a reflective surface

           P = S / c

Where c is the speed of light and S is the pointing vector which is equal to the intensity of the radiation

The definition of Pressure is

          P = F / A

          F = P A

Newton's second law gives the relationship between force and acceleration

            F = m a

We substitute

           P A = m a

           a = I  A / c  m

Let's look for the radiation intensity, for this we use that the intensity in the Earth's orbit is 1360 W / m².

We must look for the intensity in the orbit would want 0.5 AU, for this we use the definition of instance

           I = P / A

             

Where P is the power of the sun's emission that is constant

         P = I A

         I₁ A₁ = I₂ A₂

Where index 1 is for Earth and 2 for the orbit at 05 AU

he area of ​​a sphere is

          A = 4 π R²

           I₂ = I₁ A₁ / A₂

           I₂ = I₁ R₁² / R₂²

           I₂ = 1360 (150 10⁶/75 10⁶)²

           I₂ = 5440 W

This is the radiation at the point of interest

Let's calculate

           a = 5440/3 10⁸   10⁶/360

           a = 5.037 10⁻²  m / s²

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Answer:

(a) a = 56.4 m/s², his acceleration a, in multiples of gravity g, is 5.76 g

(b) a = -201.43 m/s², his deceleration -a, in multiples of gravity g, is -20.56 g

Explanation:

(a)

When moving upwards, the initial velocity, u = 0 (he accelerated from rest)

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time of  motion during this acceleration, t = 5 s

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time of  motion during this deceleration, t = 1.4 s

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1.4a = -282

a = -282 / 1.4

a = -201.43 m/s²

Ratio of his deceleration, -a to gravity, g = -a/g = 201.43 / 9.8 = 20.56

a = -20.56 g

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