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3 years ago

Birdman is flying horizontally at a

Physics

1 answer:

Natali5045456 [20]3 years ago

7 0

Answer:

117.88m

Explanation:

We can use the formula [ s = ut + 1/2at^2 ] to solve this problem.

We know that constant acceleration is a = 9/8m/a^2, the initial velocity is 0, and the height is 87 so the only variable we need to solve for is "t".

87 = 0t + 1/2(9.8)(t^2)

t = √174/9.8

t = 4.21s

Now multiply the time by the speed given.

28m/s * 4.21s = 117.88m

Best of Luck!

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CHEGG 42 mT magnetic field points due west. If a proton of kinetic energy 9 x 10-12 J enters this field in an upward direction,

alexdok [17]

Answer:

The magnitude of the Force is $F = 697 *10^{-15}N$ and the direction is South

Explanation:

From the question we are told that

The magnetic field point due west and since East point toward the positive x -axis $(i)$ then this magnetic field would be mathematically represented as

$\= B = 42(-i)mT = 42*10^{-3} (-i) T$

Now from the question we are told that the kinetic energy is

$KE = 9*10^{-12}J$

Now this kinetic energy can be mathematically represented as

$KE = \frac{1}{2}mv^2$

Where m is the mass of proton which has a general value of

$m = 1.67*10^{-27}kg$

Now making the subject of the formula

$v = \sqrt{\frac{KE}{0.5 * m} }$

Substituting values we have

$v = \sqrt{\frac{9*10^{-12}}{0.5 * 1.67*10^{-27}} }$

$= 10.37*10^7m/s$

Now from the question we are told that proton is moving upward which is in the positive z direction so the velocity of the proton would be in the positive

So the velocity would be

$\= v = 10.37*10^{7} \r k \ m/s$

Now the magnetic Force can be mathematically represented as

$\= F = q \= v * \= B$

Where q is the charge on the proton which has a general value of $q =1.6*10^{-19}C$

Now substituting the value

$\= F = 1.6*10^{-19 } * (10.37 *10^7) \r k * (42 *10^{-3})(-i)$

$= 697*10^{-15} J$

Now according to Fleming's left hand rule the direction of the magnetic force is south toward the negative Y - direction $(-j)$

So the force can be denoted as

$\= F = 697*10^{-15}(-j) N$

6 0

3 years ago

A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.

Jobisdone [24]

Answer:

F=507.7N

Explanation:

According to Newton's second law:

$\sum F=m.a$

in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:

$\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\$

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.

$F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N$

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3 years ago

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xenn [34]

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In the absence of friction, if a force acting on a moving object stops acting, the object will

murzikaleks [220]

Answer:

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A scientist runs an electric current along a wire. A magnetic compass is placed near the wire. The scientist observes that whene

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The magnetic field causes deflection of the needle of a compass . The electric current causes a magnetic field around the wire due to which the compass needle moves.

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