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2 years ago

A room has a heater on one side and

Physics

1 answer:

Serjik [45]2 years ago

5 0

Answer:

the warm air would be up and cool would be down

Explanation:

warm air is less dense and cool air is more dense

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Which type of galaxy is too small for gravity to form it into an easily describable shape?

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If you think about it, irregular galaxies dont really have a describable shape, as you can tell by the name. So B.

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3 years ago

Read 2 more answers

What happens with alpha, beta, and gamma radiation?

tresset_1 [31]

I'm sorry but I don't really understand the question. What is the quest actually asking???

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4 years ago

If Patricia worked 40 hours this week and her paycheck shows that her gross pay is $ 340 , what is her hourly wage?

GrogVix [38]

For 40 hours, she gets paid $340
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3 years ago

Design a solution that can monitor and minimize the melting of sea ice caused by human activity

dedylja [7]

Answer:

CO2 emissions from fossil fuel burning should be minimized at all cost. The CO2 are gotten when the carbons from hydrocarbons react with air(oxygen). This gas erodes the ozone layer which makes the melting of ice caps faster due to increased amount of heat radiations on the earth. This is the only best and permanent solution to the reduction of the amount of heat rays on the earth which is a global problem.

Objects which reflects back the sunrays could also be inserted into the sea to prevent the melting of the ice caps.

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3 years ago

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward

Vladimir79 [104]

Answer:

The answer is " $1.01 \times 10^{-13}$ "

Explanation:

Using the law of conservation for energy. Equating the kinetic energy to the potential energy.

$KE=U=\frac{kqq'}{r}\\\\$

Calculating the closest distance:

$\to r=\frac{kqq'}{KE}\\\\$

$=\frac{k(2e)(79e)}{KE}\\\\=\frac{k(2)(79)e^2}{KE}\\\\=\frac{9.0\times 10^9 \ N \cdot \frac{m^2}{c}(2)(79)(1.6 \times10^{-19} \ C)^2}{(2.25\ meV) (\frac{1.6 \times 10^{-13} \ J}{1 \ MeV})}\\\\$

$=\frac{9.0\times 10^9 \times 2\times 79\times 1.6 \times10^{-19}\times 1.6 \times10^{-19} }{(2.25 \times 1.6 \times 10^{-13}) }\\\\=\frac{3,640.32\times 10^{-29}}{3.6 \times 10^{-13} }\\\\=\frac{3,640.32}{3.6} \times 10^{-16}\\\\=1011.2 \times 10^{-16}\\\\=1.01 \times 10^{-13}$

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3 years ago