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Katen [24]
3 years ago
7

Who was on the grand committee

Chemistry
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

European Union was on grand committee

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The behavior of real gases most closely resembles that of ideal gases under conditions of
blsea [12.9K]
High temperature and low pressure. At high temperature, the kinetic energy of the gas particles increases and they move farther from each other. At low pressure, the gas particles are less likely to collide with each other. 
8 0
3 years ago
The half-life of carbon-14 is 5,730 years. How many grams of parent material will remain from a 200-gram sample after 3 half-liv
Alex17521 [72]

Answer:

The answer to your question is 25 grams

Explanation:

Data

half-life = 5730 years

sample = 200 g

after 3 half-lives

Process

Calculate the amount of sample after one, two and three half-lives.

After each half-life, that of sample is half the previous amount.

                         Number of half-lives           Amount of sample

                                       0                                        200 g

                                        1                                         100 g

                                        2                                          50 g

                                       3                                           25 g

4 0
3 years ago
In a chemical reaction, one of the chemical reactants is present in______ to make sure that the limiting reagent is completely c
Nata [24]

Answer: excess

Explanation: i guesses and got the answer right

8 0
2 years ago
Determine the molarity of a solution formed by dissolving 97.7 g libr in enough water to yield 750.0 ml of solution.
rewona [7]

Answer:

1.5 M.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

<em>M = (no. of moles of LiBr)/(Volume of the solution (L).</em>

<em></em>

∵ no. of moles of LiBr = (mass/molar mass) of LiBr = (97.7 g)/(86.845 g/mol) = 1.125 mol.

Volume of the solution = 750.0 mL = 0.75 L.

∴ M = (no. of moles of luminol)/(Volume of the solution (L) = (1.125 mol)/(0.75 L) = 1.5 M.

3 0
3 years ago
Read 2 more answers
What was the weight percent of water in the hydrate before heating?
DedPeter [7]
Data:

weight of water before heating = 0.349

weight of hydrate before heateing = 2.107

Formula:

Weight percent of water = [ (weight of water) / (weight of the hydrate) ] * 100

Solution:

Weight percent of water = [ 0.349 / 2.107] * 100 ≈ 16.6 %

Answer: 16.6%
3 0
3 years ago
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