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Katen [24]
3 years ago
7

Who was on the grand committee

Chemistry
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

European Union was on grand committee

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What is the percent mass oxygen in calcium carbonate (CaCo3)?
Gnoma [55]
  <span>Step 1 is to determine the mass of each part 
Mass of Ca is 40.08 g 
Mass of C is 12.01 g 
Mass of O is 16.00 x 3 = 48.00 g 
Step 2 is to determine the total mass of the compound 
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g 

Step 3 is to determine the % of each part using the following formula: 
Mass of part / total mass x 100 = 

40.08 / 100.09 x 100 = 40.04 % Ca 

12.01 / 100.09 x 100 = 12.00 % C 

48.00 / 100.09 x 100 = 47.96 % O 

Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :) 
40.04 
+12.00 
+47.96 
=100.00</span><span>
</span>
4 0
2 years ago
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Which of the following is most likely to cause the particles in a chemical change to slow down
Nady [450]
C. Lowering the temperature

At the lower temperature, particles have less kinetic energy, so they move slower.



7 0
3 years ago
What is the relationship between the number of protons and the number of electrons in an atom?
aleksley [76]
In a neutral atom they are both equal, and their even quantities makes the atom neutral...
6 0
3 years ago
How many moles of S are in 35.4 g of (C3H5)2S?
alexandr402 [8]
<span>0.310 moles First, look up the atomic weights of the elements involved. Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight sulfur = 32.065 Molar mass (C3H5)2S = 6 * 12.0107 + 10 * 1.00794 + 32.065 = 114.2086 g/mol Moles (C3H5)2S = 35.4 g / 114.2086 g/mol = 0.309959145 mol Since there's just one sulfur atom per (C3H5)2S molecule, the number of moles of sulfur will match the number of moles of (C3H5)2S which is 0.310 when rounded to 3 significant digits.</span>
6 0
3 years ago
If 495 milliliters of carbon dioxide at 25°C and 101.3 kilopascals reacts with excess water, what is the theoretical yield of ca
postnew [5]

Answer:- 1.24 g

Solution:- The balanced equation for the formation of carbonic acid by the reaction of carbon dioxide with water is:

CO_2+H_2O\rightarrow H_2CO_3

From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.

Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.

we need to convert mL to L, degree C to kelvin and kilopascals to atm.

495mL(\frac{1L}{1000mL})  = 0.495 L

25 + 273 = 298 K

101.3kPa(\frac{1atm}{101.3kPa)})

= 1 atm

Ideal gas law equation is:

PV = nRT

We want to find out the n, so let's rearrange this:

n=\frac{PV}{RT}

R is the universal gas constant and it's value is \frac{0.0821atm.L}{mol.K} .

Let's pug in the values in the equation and solve it for n.

n=\frac{1*0.495}{0.0821*298}

n = 0.02 mol

To convert the moles to grams we multiply the moles by the molar mass of carbonic acid.

Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)

= 2.016+12.01+48.00

= 62.03 gram per mol (rounded to two decimal places)

Let's multiply the moles by molar mass:

0.02mol(\frac{62.03g}{mol})

= 1.24 g

So, the theoretical yield of carbonic acid is 1.24 g.


6 0
3 years ago
Read 2 more answers
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