Question

If a balloon contains 3.00 L of air that has a pressure of 36.74 psi, what is the gas volume (the volume of the balloon) once it floats to the surface?

Answer 1

Answer:

7.5 L

Explanation:

At constant temperature and number of moles, Using Boyle's law  

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,  

V₁ = 3.00 L  

V₂ = ?

P₁ = 36.74 psi = 2.5 atm (Conversion factor, 1 psi = 0.068046 atm)

P₂ = 1 atm  (Atmospheric pressure as it comes to surface)

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${2.5\ atm}\times {3.00\ L}={1\ atm}\times {V_2}$

${V_2}=\frac{{2.5}\times {3.00}}{1}\ L$

${V_2}=7.5\ L$