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nlexa [21]
3 years ago
8

Copper reacts with silver nitrate through single replacement.

Chemistry
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

  • Part a) 0.0104 moles copper(II) nitrate.

  • Part b)

            i) 0.0418 mole Cu

            ii) 0.0209 mol Ag NO₃

Explanation:

<u>1) Balanced chemical reaction (single replacement):</u>

In a single replacement reaction a more acitve metal (Cu) replaces a less active metal (Ag)

  • Cu + 2 Ag NO₃ → Cu (NO₃)₂ + 2 Ag

<u>2) Mole ratio: </u>

  • 1 mole Cu : 2 mole Ag NO₃ : 2 mole Ag

<u />

<u>3) Moles of Ag</u>

  • n = mass in grams / atomic mass
  • atomic mass of Ag: 107.868 g/mol
  • n = 2.25 g / 107.868 g/mol = 0.0209 mol Ag

<u>4) Moles of copper(II) nitrate:</u>

  • Set the proportion using the mole ratio:
  • 2 mole Ag / 1 mole Cu (NO₃)₂ = 0.0209 mole Ag / x
  • Solve: x = 0.0209 / 2 mole Cu (NO₃)₂ =  0.0104 moles Cu(NO₃)₂

That is the answer of part a: 0.0104 moles copper(II) nitrate.

<u>5) Moles of each reactant</u>

i) Cu:

  • Set a proportion using the theoretical mole ratio

        1 mole Cu / 2 mole Ag = x / 0.0209 mol Ag

  • Solve for x: x = 0.0209 / 2 mole Cu = 0.0418 mole Cu

ii) Ag NO₃

  • Set a proportion using the teoretical mole ratio

   

       2 mole Ag NO₃ / 2 mole Ag = x / 0.0209 mole Ag

  • Solve for x: x = 0.0209 mol Ag NO₃
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