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7nadin3 [17]
3 years ago
6

Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arr

ow. Pb ( N O ₃ ) ₂ (aq) + 2 K I (aq) → Pb I ₂ + 2 K N O ₃ ☐⁴⁻ ☐³⁻ ☐²⁻ ☐⁻ ☐⁺ ☐²⁺ ☐³⁺ ☐⁴⁺ 1 2 3 4 5 6 7 8 9 0 ☐₁ ☐₂ ☐₃ ☐₄ ☐₅ ☐₆ ☐₇ ☐₈ ☐₉ ☐₀ + ( ) → ⇌ (s) (l) (g) (aq) NR O K I N Pb Reset
Chemistry
1 answer:
Alex Ar [27]3 years ago
3 0

Explanation:

The reaction is given as;

Pb ( N O ₃ ) ₂ (aq) +  K I (aq) → Pb I ₂ +  K N O ₃

To ensure the reaction is balanced, there has to be equal number of toms of each element present in both the reactant and product side of the reaction.

This leads us to;

Pb ( N O ₃ ) ₂ (aq) + 2 K I (aq) → Pb I ₂(s) + 2 K N O ₃(aq)

Ths way all atoms of elements are the same.

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Answer:

Please see the attachments

Explanation:

Please see the attachments below structures of the 3 isomers of C8H18 that contain 3 methyl branches on the main chain, 2 of which are on the same carbon.

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4 0
2 years ago
What is the average yearly rate of change of carbon-14 during the first 5000 years?
erica [24]

Answer:

The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year

Explanation:

Given that the mass of the carbon 14 at the start = 5 gram

At the end of 5,000 years we will have;

A = A_0 \times e^{-\lambda \times t}

Where

A = The amount of carbon 14 left

A₀ = The starting amount of carbon 14

e = Constant = 2.71828

T_{1/2} = The half life

\lambda = 0.693/T_{1/2}

t = The time elapsed = 5000 years

λ = 0.693/T_{1/2} = 0.693/5730 = 0.0001209424

Therefore;

A = 5 × e^(-0.0001209424×5000) = 2.7312 grams

Therefore, the amount of carbon 14 decayed in the 5000 years is the difference in mass between the starting amount and the amount left

The amount of carbon 14 decayed = 5 - 2.7312 = 2.2688 grams

The average yearly rate of change of carbon-14 during the first 5000 years  is therefore;

2.2688 grams/(5000 years) = 0.0004538 grams per year

The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year.

5 0
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My favorite student weighs in at 125 pounds. How many<br>kilograms do they weigh?​
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Answer:

56.69905

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7 0
3 years ago
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