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2 years ago

What kind of glacier has pieces that breaks off as icebergs

1 answer:

5 0

There is no specific name for a glacier that break off as an iceberg. However, the part of the glacier in which this happens is called the "zone of wastage". Chunks break off in a process called "calving".

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2. Metals react with water and release hydrogen gas. Explain why non-metals do not release hydrogen gas when reacted with water.

Phantasy [73]

Answer:

Its because non-metals are unable to break the bond between the H and O ion and cannot reduce hydrogen by donating electrons

8 0

1 year ago

When the white part is on the left the moon is.??

Kazeer [188]

Answer:

Last Quarter also called Third Quarter.

Explanation:

6 0

2 years ago

nignag [31]

Answer:

Explanation:

I think it is D. Think about it- if a human jumps, they are less than the gravitational force. But, if you are greater than the gravitational force, I think you will go into space.

4 0

2 years ago

PLS HELP STOICHIOMETRY/CHEM!!!

Mariulka [41]

The molecular formula of the compound that we are required to find is the compound C4H8O8

<h3>What is empirical formula?</h3>

The empirical formula of a compound is a formula that shows the ratio of each atom present in the compound. We will start by dividing each mass with the relative atomic mass of the atom.

Carbon - 48.38 g/12 Hydrogen - 6.74 g/1 Oxygen - 53.5 g/16

Carbon - 4 Hydrogen - 6.74 Oxygen - 8.9

Dividing through by the lowest ratio;

Carbon - 4/4 Hydrogen - 6.74/4 Oxygen 8.9/4

Carbon 1 Hydrogen 2 Oxygen 2

The empirical formula is CH2O2.

To obtain the molecular formula; brainly.com/question/11588623

[12 + 2 + 32]n = 180

n = 180/[12 + 2 + 32]

n =4

The compound C4H8O8

Learn more about empirical formula:

7 0

2 years ago

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

2 years ago