Answer:
It's the button with the x, and a blank box above it.
Explanation:
Check the attachments, you'll see what it looks like. It will probably look different on your calculator, but the icon should be the same or similar.
Answer &Explanation:
From Avogadro's lawa equal volume of gas contain equal number of moles
V=N
Hence
13L=965
XL=3.2mol
Hint:as the question state is increase to iteans final mol was 3.2 but if it could state by it would mean initial moles plus adde moles ie 3.2mol)
Cross multiplication
The new volume will be
=(3.2mol×13L÷965mol)
=0.043L
Answer:
Density is a physical quantity, defined as the ratio of body mass to the volume occupied by this body. The average body density is the ratio of body weight to its volume.
Since the mass in a body can be distributed unevenly, a more adequate model defines the density at each point of the body as a derivative of mass over volume.
Thus, to obtain the density of a sample, its mass must be divided by its volume. Thus, the density of the sample is 1.2 / 1.1, that is, 1.09 g/cm3.
Answer:
0.22 mol HClO, 0.11mol HBr.
0.25mol NH₄Cl, 0.12 mol HCl
Explanation:
A buffer is defined as a mixture in solution between weak acid and its conjugate base or vice versa.
Potassium hypochlorite (KClO) could be seen as conjugate base of HClO (Weak acid). That means the addition of <em>0.22 mol HClO </em>will convert the solution in a buffer. HBr reacts with KClO producing HClO, thus, <em>0.11mol HBr</em> will, also, convert the solution in a buffer. 0.23 mol HBr will react completely with KClO and in the solution you will have only HClO, no a buffering system.
Ammonia (NH₃) is a weak base and its conjugate base is NH₄⁺. That means the addition of <em>0.25mol NH₄Cl</em> will convert the solution in a buffer. Also, NH₃ reacts with HCl producing NH₄⁺. Thus, addition of<em> 0.12 mol HCl</em> will produce NH₄⁺. 0.25mol HCl consume all NH₃.
<h3><u>Answer</u>;</h3>
No, a precipitate does not form
<h3><u>Explanation</u>;</h3>
- Precipitation involves mixing or combining solutions that contain soluble ionic compounds to form an insoluble ionic compound by a reaction.
- Sodium acetate and ammonium sulfate are both soluble ionic compounds, which implies that they exist as ions in aqueous solution.
- <em><u>When they combine they form NH4CH3COOH and sodium sulfate, Na2SO4, which are both soluble salts, as all salts of ammonium and sodium are soluble.</u></em>
- <em><u>Both ammonium acetate and sodium sulfate are soluble because there are no anions that can form an insoluble solid with NH4+ and Na+ cations. </u></em>
