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2 years ago

Chemical Equations and Reactions WS

Chemistry

1 answer:

ruslelena [56]2 years ago

7 0

Answer:

1,1,1

decomposition reaction

Explanation:

The reaction equation is given as:

_Ca(OH)₂ → _CaO + _H₂O

This reaction is a decomposition reaction in which a single reactant breaks down to give two or more products.

To balance the equation, we assign variables a, b and c, then we use a mathematical approach to solve the problem;

aCa(OH)₂ → bCaO + cH₂O

Conserving Ca : a = b

O: 2a = b + c

H: 2a = 2c

let a = 1, b = 1 , c = 1

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A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to

Drupady [299]

Answer : The final temperature of the mixture is $29.6^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of iron = $0.499J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of iron = 39.9 g

$m_2$ = mass of water = $Density\times Volume=1g/mL\times 50.0mL=50.0g$

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of iron = $78.1^oC$

$T_2$ = initial temperature of water = $25.0^oC$

Now put all the given values in the above formula, we get

$(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC$

$T_f=29.6^oC$

Therefore, the final temperature of the mixture is $29.6^oC$

8 0

3 years ago

Can someone help me please ?

KiRa [710]

Answer: B

Explanation:

Graph 1 represents an endothermic reaction, Graph 2 represents an exothermic reaction.

***If you found my answer helpful, please give me the brainliest. :) ****

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