Answer:
Explanation:
C = 49.48
H = 5.19
O = 16.48
N = 28.85
ratio of moles
= 49.48 / 12 : 5.19 / 1 : 16.48 / 16 : 28.85 / 14
= 4.123 : 5.19 : 1.03 : 2.06
= 4 : 5 : 1 : 2
so the empirical formula = C₄ H₅O N₂
Let molecular formula = ( C₄ H₅ON₂ )ₙ ,
n ( 48 + 5 + 16 + 28 ) = 119.19
97 n = 194.19
n = 2 ( approx )
molecular formula = C₈ H₁₀O₂ N₄
The limiting reactant is salicylic acid (C₇H₆O₃).
Explanation:
We have the following chemical reaction where salicylic acid (C₇H₆O₃) reacts with acetic anhydride (C₄H₆O₃) to form acetylsalicylic acid (C₉H₈O₄) and acetic acid (C₂H₄O₂):
C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + C₂H₄O₂
We have started with 70.0 g of salicylic acid (C₇H₆O₃) and 80.0 g acetic anhydride (C₄H₆O₃).
First we calculate the number of moles of each reactant:
number of moles = mass / molar weight
number of moles of salicylic acid = 70 / 138 = 0.507 moles
number of moles of acetic anhydride = 80 / 102 = 0.784 moles
We see from the chemical reaction that 1 mole of acetic anhydride (C₄H₆O₃) reacts with 1 mole of salicylic acid (C₇H₆O₃) so 0.784 moles of acetic anhydride (C₄H₆O₃) will react with 0.784 mole of salicylic acid (C₇H₆O₃) but we only have 0.507 moles of salicylic acid (C₇H₆O₃). The limiting reactant is salicylic acid (C₇H₆O₃).
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limiting reactant
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Answer:The Old Sow whirlpool is located off the southwestern shore of Deer Island, New Brunswick between the island and Eastport, Maine. The whirlpool is caused by variations in local bathymetry combined with the extreme tidal range of the Western Passage where waters exchange between Passamaquoddy Bay and the Bay of Fundy.
Explanation:
Answer:
0.558mole of SO₃
Explanation:
Given parameters:
Molar mass of SO₃ = 80.0632g/mol
Mass of S = 17.9g
Molar mass of S = 32.065g/mol
Number of moles of O₂ = 0.157mole
Molar mass of O₂ = 31.9988g/mol
Unknown:
Maximum amount of SO₃
Solution
We need to write the proper reaction equation.
2S + 3O₂ → 2SO₃
We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.
So we simply compare the molar relationship between sulfur and product formed to solve the problem:
First, find the number of moles of Sulfur, S:
Number of moles of S =
Number of moles of S = = 0.558mole
Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:
2 mole of Sulfur produced 2 mole of SO₃
Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃