Explanation:
It is given that 44.45 g of hydrocarbon gas produces 2649 kJ or
of heat.
Also here, 1 lb = 453.592 g.
Therefore, amount of energy released by 453.592 g of hydrocarbon gas will be calculated as follows.

= 
It is known that 1 J =
.
Hence,
= 
= 7.508 Kwh
Thus, we can conclude that the combustion of exactly one pound of this hydrocarbon gas produce 7.508 Kwh energy.
When 1-bromo propane is reacted with sodium metal, the propane and sodium bromide are formed.
- Propane and sodium bromide are produced when the 1-bromo propane is reacted with sodium metal.
- The Bromine which is present in the 2-bromopropane is removed through hydrogenation and combines with the sodium metal which results in the production of propane and sodium bromide.
- So we can conclude that propane and sodium bromide are produced when the 1-bromo propane is reacted with sodium metal.
Learn more about 1-bromo propane here: brainly.com/question/25597694
Learn more: brainly.com/question/25952418
What the first person said lol
Answer:
The root mean squared velocity for CF2Cl2 is 
Explanation:
From the question we are told that
The temperature is 
Root Mean Square velocity is mathematically represented as

Where T is the temperature
MW is the molecular weight of gas
R is the gas constant with a value of 
For CF2Cl2 its molecular weight is 0.121 kg/mol
Substituting values


Answer:
2 atoms of nitrogen are present.