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Tcecarenko [31]
3 years ago
15

Under which conditions of temperature and pressure does oxygen gas behave least like an ideal gas?

Chemistry
2 answers:
aleksandrvk [35]3 years ago
6 0
The answer is (2) low temperature and high pressure so oxygen gas behave least like an ideal gas :)))
i hope this be helpful
* merry Christmas *
GuDViN [60]3 years ago
6 0

Answer:

The oxygen gas behaves less like an ideal gas under the conditions of low temperature and high pressure (option 2)

Explanation:

The ideal gas refers to a hypothetical gas composed of molecules that follow a few rules:  

  • Formed by point particles.  That is, the molecules of an ideal gas, in themselves, do not occupy any volume.
  • The molecules do not interact with each other and move randomly.

This law does not apply when the pressure is so high, or the temperature is so low, where the gas is about to become liquid.

So generally, <u><em>the oxygen gas behaves less like an ideal gas under the conditions of low temperature and high pressure (option 2)</em></u>

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The combustion of 44.45 grams of a hydrocarbon gas mixture releases 2,649 kJ of heat. How much energy, in kWh, will the combusti
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Explanation:

It is given that 44.45 g of hydrocarbon gas produces 2649 kJ or 2649 \times 10^{3} J of heat.

Also here, 1 lb = 453.592 g.

Therefore, amount of energy released by 453.592 g of hydrocarbon gas will be calculated as follows.

              \frac{2649 \times 10^{3} J \times 453.592 g}{44.45 g}

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It is known that 1 J = 2.778 \times 10^{-7} Kwh.

Hence, 27.03 \times 10^{6} J = 27.03 \times 10^{6} J \times 2.778 \times 10^{-7} Kwh/J

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3 years ago
Predict the product 1-bromo propane is treated with sodium metal
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When 1-bromo propane is reacted with sodium metal, the propane and sodium bromide are formed.

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Learn more about 1-bromo propane here: brainly.com/question/25597694

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What the first person said lol
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Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat
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Answer:

The root mean squared velocity for CF2Cl2 is  v_{rms}= 207.06 m/s

Explanation:

From the question we are told that

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Root Mean Square velocity is mathematically represented as

      v _{rms} = \sqrt{\frac{3RT}{MW} }

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For  CF2Cl2 its molecular weight is  0.121 kg/mol

     Substituting values

  v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }

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