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Tcecarenko [31]
3 years ago
15

Under which conditions of temperature and pressure does oxygen gas behave least like an ideal gas?

Chemistry
2 answers:
aleksandrvk [35]3 years ago
6 0
The answer is (2) low temperature and high pressure so oxygen gas behave least like an ideal gas :)))
i hope this be helpful
* merry Christmas *
GuDViN [60]3 years ago
6 0

Answer:

The oxygen gas behaves less like an ideal gas under the conditions of low temperature and high pressure (option 2)

Explanation:

The ideal gas refers to a hypothetical gas composed of molecules that follow a few rules:  

  • Formed by point particles.  That is, the molecules of an ideal gas, in themselves, do not occupy any volume.
  • The molecules do not interact with each other and move randomly.

This law does not apply when the pressure is so high, or the temperature is so low, where the gas is about to become liquid.

So generally, <u><em>the oxygen gas behaves less like an ideal gas under the conditions of low temperature and high pressure (option 2)</em></u>

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Part iii. Is the dissolution reaction of ammonium nitrate enthalpy favored?
lesya [120]

Answer:

No, it is not enthalpy favored since the chemical system gains energy.

Explanation:

The dissolution of ammonium nitrate in water is an endothermic process.

Endothermic process requires the system to gain energy to can dissolve the particles in water.

So, the reaction is not enthalpy favored.

3 0
3 years ago
What is the molarity of 60.0 grams of NaOH dissolved in 750 milliliters of water?
Bumek [7]

<u>Answer:</u>

The correct answer option is B) 2.0 M.

<u>Explanation:</u>

We are given the number of grams of NaOH (Sodium Chloride) which are dissolved in 750 milliliters of water and we are to find its molarity.

We know the formula of molarity:

<em>Molarity =  (mass * 1000) / (volume * molecular mass)  </em>

Volume = 750 ml = 750 cm^3

Molecular mass = 40  

Mass = 60 grams

Substituting these values in the above formula:

Molarity = \frac{(60*1000)}{750*40} = 2.0 M

8 0
3 years ago
Which two elements make up the greatest percentages by mass in Earth’s crust?
yuradex [85]
<h2><u>Answer</u> :</h2>

The most appropriate option is :

\hookrightarrow \bf2. \:  \mathrm{ \underline{oxygen \:  \: and \:  \: silicon}}

Since, they are the most abundant elements found in Earth's Crust.

  • Oxygen (46%)

  • Silicon (28%)

\circ  { \underline{ \boxed{ \sf{ \color{green}{ \mathrm{hope \:  \: it \:  \: helps \:  \: you .....}}}}}}∘

4 0
2 years ago
If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p
Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

The question ask us to calculate the percentage yield of NaCl.

The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

as

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

molar mass of NaCl = 23 + 35.5 = 58.5 g

1 mole of NaHCO3 = 84 g

1 mole of NaCl  = 58.5 g

since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

Theoretical yield of NaCl = 585/84

Theoretical yield of NaCl  = 6.9642857143 g

percentage yield of NaCl = actual yield/theoretical yield × 100

percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

3 0
3 years ago
Read 2 more answers
In an experiment, hydrochloric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate was form
iris [78.8K]

Answer:

I think that the trend that would be seen in the time column of the data table would be that the number of seconds would increase. I know this because for each flask, the concentration of sodium thiosulfate decreases, since less of it is being mixed with more water. Also, when the concentration of a substance decreases, then the reaction rate also decreases, as there will be fewer collisions with sulfuric acid if there are fewer moles of sodium thiosulfate. When there are fewer collisions in a reaction, the reaction itself will take longer, and so when the sodium thiosulfate is diluted, the reaction takes more time.

Explanation:

<em>I verify this is correct. </em>

6 0
2 years ago
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