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mrs_skeptik [129]
3 years ago
8

As your skateboard coasts uphill, your speed changes from 3 m/s to 1 m/s in

Physics
1 answer:
vlada-n [284]3 years ago
7 0

Answer:

a=-0.33\ m/s^2

Explanation:

<u>Accelerated Motion</u>

The acceleration of a moving body is defined as the relation of change of speed (or velocity in vector form) with the time taken. The formula is given by

\displaystyle a=\frac{\Delta v}{t}

Or, equivalently

\displaystyle a=\frac{v_f-v_o}{t}

Where vf and vo are the final and initial speeds respectively. The problem gives us these values: v0 = 3 m/s, vf = 1 m/s, t = 3 seconds. Computing a

\displaystyle a=\frac{1-3}{3}=-0.33\ m/s^2

The negative sing of a indicates there is deceleration or decreasing speed

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A truck covers 40.0 m in 7.10 s while smoothly slowing down to a final velocity of 2.75 m/s.. (a) Find the truck's original spee
ser-zykov [4K]
D = vo t - at²/2
v = vo - at
40 m = vo · 7.10 - a · ( 7.10 )²/2
40 m = 7.10 vo - a· 50.41/2
40 m = 7.10 vo - 25.205 a
2.75 m/s = vo - 7.10 a   ⇒  a = ( vo - 2.75 )/ 7.10
40 = 7.10 vo - 25.205 · ( vo - 2.75 ) / 7.10
40 = 7.1 vo - 3.55 vo + 9.7625
3.55 vo = 30.2375 
vo = 30.2375 : 3.55 = 8.5176 m/s
Answer: the truck`s original speed is 8.5176 m/s.
 
4 0
4 years ago
What is a voltage ? What is potential Difference ?
ANEK [815]

Answer:

A voltage is an electromotive force or potential difference expressed in volts. A potential difference is the difference of electrical potential between two points

8 0
3 years ago
If the solar system shrank so that the sun were located just one centimeter from Earth, about how far away could you find the ne
DedPeter [7]
E                  S                                                               *

The "E" represents Earth, "S" represent Sun, and the "*" represents the nearest star(which is Proxima Centauri).

The main thing to worry about here is units, so ill label everything out.
D'e,s'(Distance between earth and sun) = .<span>00001581 light years
D'e,*'(Distance between earth and Proxima) = </span><span>4.243 light years

Now this is where it gets fun, we need to put all the light years into centimeters.(theres alot)
In one light year, there are </span>9.461 * 10^17 centimeters.(the * in this case means multiplication) or 946,100,000,000,000,000 centimeters.

To convert we multiply the light years we found by the big number.
D'e,s'(Distance between earth and sun) = 1.496 * 10^13 centimeters<span>
D'e,*'(Distance between earth and Proxima) = </span><span>4.014 * 10^18 centimeters
</span>
Now we scale things down, we treat 1.496 * 10^13 centimeters as a SINGLE centimeter, because that's the distance between the earth and the sun. So all we have to do is divide (4.014 * 10^18 ) by (<span>1.496 * 10^13 ).
Why? because that how proportions work.

As a result, you get a mere 268335.7 centimeters.

To put that into perspective, that's only about 1.7 miles

A lot of my numbers came from google, so they are estimations and are not perfect, but its hard to be on really large scales.</span>
8 0
3 years ago
The volume control on a stereo is designed so that three clicks of the dial increase the output by 10 dB. How many clicks are re
Rzqust [24]

Answer:

300 clicks...

Explanation:

Output on 3 clicks = 10 dB

Increasing 10 by a factor of 100 equals 1000 dB so,

Its simple math, clicks will also increase in the same ratio and it shall take 300 clicks to increase the volume by a factor of 100.

3 0
3 years ago
A rotating cylinder about 16 km long and 7.8km in diameter is designed to be used as a space colony.
Semmy [17]

Answer:

0.05 rad/s

Explanation:

7.8 km = 7800 m

For the residents inside the space cylinder to experience the same gravitation acceleration g = 9.81m/s2 on Earth, the centripetal acceleration must be the same as g

a = g

But centripetal acceleration is product of angular velocity squared and radius of rotation r

\omega^2r = 9.81

\omega^2 d/2 = 9.81

\omega^2 = \frac{2*9.81}{d} = \frac{19.62}{7800} = 0.0025

\omega = \sqrt{0.0025} = 0.05 rad/s

3 0
3 years ago
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