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Angelina_Jolie [31]

3 years ago

13

I tried the experiment of dropping candy into a liter of soda and caused a big explosion of foamy soda. Is that a physical or Ch

emical Change

1 answer:

Aleks04 [339]3 years ago

6 0

Answer:

physical change

Explanation:

its a physical change because its still soda it hasn't changed into anything else than what it already is

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Which of the following statements are true? (There may be more than one correct choice.)

Luba_88 [7]

Answer:

option (A)

Explanation:

According to the Archimede's principle, when a body s immersed partly or wholly in a liquid, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in the weight of body.

The weight of liquid displaces by the body is equal to the loss in weight of body.

Thus, option (a) is true.

5 0

3 years ago

Does the sun fuse hydrogen into helium or vice versa?

NikAS [45]

Hydrogen has the smaller, lighter, simpler nucleus.
Helium has the larger, heavier, more complex nucleus.
Hydrogen nuclei are fused to form helium nuclei.
When that happens, energy is released.

6 0

3 years ago

Find the work performed when the given force f f is applied to an object, whose resulting motion is represented by the displacem

Ahat [919]

work = force x distance

fd foot pounds

3 0

3 years ago

Peg P is driven by the forked link OA along the path described by r = eu, where r is in meters. When u = p4 rad, the link has an

8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 $m/s^2$ where as radial the component of acceleration is 8.77 $m/s^2$

Explanation:

As per the given data

u=π/4 rad

ω=u'=2 rad/s

α=u''=4 rad/s

$r=e^u$

So the transverse component of acceleration are given as

$a_{\theta}=(ru''+2r'u')\\$

Here

$r=e^u\\r=e^{\pi/4}\\r=2.1932 m$

$r'=e^u.u'\\r'=2.1932 \times 2\\r'=4.3864 m$

So

$a_{\theta}=(ru''+2r'u')\\a_{\theta}=(2.1932\times 4+2\times 4.3864 \times 2)\\a_{\theta}=26.32 m/s\\$

The transverse component of acceleration is 26.32 $m/s^2$

The radial component is given as

$a_r=r''-r\theta'^2$

Here

$r''=e^u.u'^2+e^u u''\\r''=2.1932 \times (2)^2+2.1932\times 4\\r''=17.5456 m$

So

$a_r=r''-ru'^2\\a_r=17.5456-2.1932\times (2)^2\\a_r=8.7728 m/s^2$

The radial component of acceleration is 8.77 $m/s^2$

6 0

3 years ago

Look at the circuit diagram. Which of these components is part of the circuit?

Roman55 [17]

Answer:

b ac power source

Explanation:

ieififuffucjcjcicogore8e8e9e9e9e9ew0ww0w0w

7 0

3 years ago