The dimensions of the paper are 9 by 5 inches
<h3>How to determine the dimensions?</h3>
Let x represent the length and y, the width
The given parameters are:
Perimeter, P = 28
Area, A = 45
So, we have
P = 2(x + y) = 28
A = xy = 45
Rewrite as:
2(x + y) = 28
xy = 45
By trial by error, we have:
x = 9 and y = 5
This can be proved as follows:
2(9 + 5) = 28--- true
9 * 5 = 45 --- true
Hence, the dimensions of the paper are 9 by 5 inches
Read more about perimeter and area at:
brainly.com/question/11957651
#SPJ1
Erin ran 3 1/2 more lap then last week with a total of 12 this week. to solve divide 30 by 2 1/2 and then subtract 8 1/2
Answer:
$1,494
Step-by-step explanation:
the total cost multiplied by the number of family members
<h2><u><em>xoxo,</em></u></h2><h2><u><em>your highness...</em></u></h2>
Answer: The vertical stretch of 5 in the equation y = x is defined by
.
Explanation:
The given equation is,
![y=x](https://tex.z-dn.net/?f=y%3Dx)
It can be written as,
![f(x)=x](https://tex.z-dn.net/?f=f%28x%29%3Dx)
The function is defined as
.
If
, then the function has a vertical stretch by a factor of S units.
If
, then the function has a vertical shrink by a factor of S units.
Since we have to find the vertical stretch of 5 in the equation y = x.
![y=5f(x)](https://tex.z-dn.net/?f=y%3D5f%28x%29)
![y=5x](https://tex.z-dn.net/?f=y%3D5x)
The below figure shows the graph of y = x and
.
add the 2 equations together
x+y =9
x-y =7
----------
2x = 16
divide by 2
x=8
x+y =9
substitute in x=8
8+y =9
subtract 8 from each side
y =1
(8,1)