All categories

3 years ago

Ria is performing an experiment in chemistry class with a certain

Mathematics

1 answer:

icang [17]3 years ago

4 0

Answer:

Part A: Growing

Part B: 100

Part C: 8100

Step-by-step explanation:

You might be interested in

Solve for y. 8y -11y – -2 = -16 y =

polet [3.4K]

8y - 11y - -2 = -16
-3y + 2 = -16
-3y = -16 - 2 = -18
y = -18/-3 = 6
y = 6

5 0

3 years ago

WHO WANTS TO HELP ME PLEASE⁉️

NISA [10]

Answer:

x= 69 y = 111

Step-by-step explanation:

if it works can i have brainliest?

5 0

3 years ago

10 POINTS! Please help ASAP<br><br> How do I find the perimeter of a trapezoid?

KengaRu [80]

Use the triangle formed by the height of the trapezoid to find the lengths of the two sides of the trapezoid and the length of b2:

tan(60)=oppositeadjacent . Adjacent=5tan(60)=2.89 cm.

This finds the base of the triangle, which can be added twice to b1 to find b2: b2=8+2.89+2.89=13.78 cm.

Now, use the same triangle to find the length of the sides.

sin(60)=oppositehypotenuse . Hypotenuse=5sin(60)=5.77 cm.

Lastly, add all of the lengths together: b1+b2+2(l)=8+(2.78+2.78+8)+2(5.77)=33.32 cm.

5 0

3 years ago

Yo can someone help me with this? (Links = report)

Troyanec [42]

Answer:

Step-by-step explanation:

12.6 divided by pi= 4.01

sqaure root of 4 is 2

7 0

3 years ago

A model rocket is launched directly upward at a speed of 20 meters per second from the ground. The function f(t)=−4.9t2+20t, mod

Nataly [62]

Answer:

The rocket will reach its highest point about 2.04 seconds.

Step-by-step explanation:

The function:

$f(t)=-4.9t^2+20t$

Models the relationship between the height of the rocket and the time after launch t in seconds.

Since this is a quadratic function, the rocket will reach its highest point at its vertex. The vertex of a quadratic is given by:

$\displaystyle \Big(-\frac{b}{2a}, f\Big(-\frac{b}{2a}\Big)\Big)$

In this case, a = -4.9, b = 20, and c = 0. Thus:

$\displaystyle t=\frac{-(20)}{2(-4.9)}=\frac{10}{4.9}\approx 2.04$

The rocket reaches its maximum height after 10/4.9 or about 2.04 seconds.

Further Notes:

Then the maximum height of the rocket will be f(10/4.9):

$\displaystyle f\Big(\frac{10}{4.9}\Big)=-4.9\Big(\frac{10}{4.9}\Big)^2+20\Big(\frac{10}{4.9}\Big)\approx20.41\text{ feet}$

4 0

3 years ago