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SpyIntel [72]
4 years ago
14

People benefit by participating in the market because

Physics
1 answer:
solniwko [45]4 years ago
3 0

Answer:

Market participation allows individuals to specialize and, with trade, ultimately consume more.

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g In a certain binary-star system, each star has the same mass which is 8.2 times of that of the Sun, and they revolve about the
Mademuasel [1]

To solve this problem it is necessary to apply the concepts related to the Third Law of Kepler.

Kepler's third law tells us that the period is defined as

T^2 = \frac{4\pi^2 d^3}{2GM}

The given data are given with respect to known constants, for example the mass of the sun is

m_s = 1.989*10^{30}

The radius between the earth and the sun is given by

r = 149.6*10^9m

From the mentioned star it is known that this is 8.2 time mass of sun and it is 6.2 times the distance between earth and the sun

Therefore:

m = 8.2*1.989*10^{30}

d = 6.2*149.6*10^6

Substituting in Kepler's third law:

T^2 = \frac{4\pi^2 d^3}{2}

T^2 = \frac{4\pi^2(6.2*149.6*10^9)^3}{2(6.674*10^{-11} )(8.2*1.989*10^30 )}

T=\sqrt{\frac{4\pi^2(6.2*149.6*10^9)^3}{2(6.674*10^{-11} )(8.2*1.989*10^30)}}

T = 120290789.7s

T = 120290789.7s(\frac{1year}{31536000s})

T \approx 3.8143 years

Therefore the period of this star is 3.8years

7 0
3 years ago
As a ship comes into view over the horizon the top appears before the rest of the ship how does this demonstrate the earth is sp
valina [46]
Since its a sphere, the top is seen first because its the tallest part if the ship. If the earth was flat, the whole ship would be seen.
7 0
3 years ago
Where is UTC the local time?
Dmitrij [34]

UTC is generally adopted as the local time at Prime Meridian (PM).

<h3>What is UTC?</h3>

UTC is an abbreviation for Coordinated Universal Time and it can be defined as a local time standard by which all clocks, time and time zones are regulated around the world.

This ultimately implies that, Coordinated Universal Time (UTC) is generally adopted as the local time at Prime Meridian (PM) because it nominally reflects mean solar time.

Read more on UTC here: brainly.com/question/14333785

#SPJ12

5 0
2 years ago
A tire 0.500 m in radius rotates at a constant rate of 200 rev/min. Find the speed and acceleration of a small stone lodged in t
arsen [322]

Answer:

v = 10.47 m/s

a = 219.32 m/s²

Explanation:

The velocity of the stone can be given by the following formula:

v = r ω

where,

v = linear velocity of the stone = ?

r = radius of tire = 0.5 m

ω = angular velocity = (200 rev/min)(2π rad/1 rev)(1 min/60 s) = 20.94 rad/s

Therefore,

v = (0.5 m)(20.94 rad/s)

<u>v = 10.47 m/s</u>

<u></u>

The acceleration of the stone will be equal to the centripetal acceleration. Therefore,

a = v²/r

a = (10.47 m/s)²/0.5 m

<u>a = 219.32 m/s²</u>

8 0
3 years ago
Light of wavelength 648.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 57.5 cm from the slit.
boyakko [2]

Answer:

71.0 \mu m

Explanation:

The formula for the single-slit diffraction is

y=\frac{n\lambda D}{d}

where

y is the distance of the n-minimum from the centre of the diffraction pattern

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light

In this problem,

\lambda=648.0 nm=6.48\cdot 10^{-7}m

D=57.5 cm=0.575 m

y=1.05 cm=0.0105 m, with n=2 (this is the distance of the 2nd-order minimum from the central maximum)

Solving the formula for d, we find:

d=\frac{n\lambda D}{y}=\frac{2(6.48\cdot 10^{-7} m)(0.575 m)}{0.0105 m}=7.10\cdot 10^{-5} m= 71.0 \mu m

6 0
3 years ago
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