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koban [17]
3 years ago
12

Explain why a real image must be produced in a camera and how the object and the lens are positioned to produce a real image whi

ch is SMALLER than the object.
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0
This is best explained through the use of an optics diagram, this is a little too complicated to explain in a short answer, and as I can't draw an appropriate diagram in this answer, I will point you to this excellent resource which explains what you have asked very well!

Go onto the BBC website (you should have access to it even if you aren't in the UK) and paste this after the BBC url,

/bitesize/intermediate2/physics/waves_and_optics/image_formation_from_lens/revision/1/
You might be interested in
________ occurs when the horizontal winds move air against mountain ranges, forcing air to rise as it passes over the mountains.
Semenov [28]
The answer would be:
Precipitation sometimes occurs when the horizontal winds move air against mountain ranges, forcing air to rise as it passes over the mountains.
This happens when the air is forced to move from low elevation to high elevation due to rising terrain. This causes the air to cool adiabatically. This increases the relative humidity and causes clouds to form, under certain conditions it can also create precipitation.
6 0
3 years ago
Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the en
satela [25.4K]

Answer:

The fence is 5feet less.

Explanation:

We need to determine

The less amount of fence required, if the enclosure has full width and reduced length, compared to full length and reduced width.

Approach & WorkingArea of lawn = 30 × 403/4th of the area of lawn = ¾(30 × 40) = 30 * 30

 When full width will be fenced, and reduced length will be fenced.

Width = 30 feet30 * L = 30 * 30Hence, length = 30 feetLength of fence needed = 2(30 + 30) = 120 feet

When full length will be fenced, and reduced width will be fenced

Length = 40 feet40 * W = 30 * 30W = 22.5 feetLength of fence needed = 2(40 + 22.5) = 125 feet

Difference in length of fence needed = 125 – 120 = 5 feet.

4 0
3 years ago
Fossils are dated using radioactive...<br><br> a. hydrogen <br> b. helium<br> c. carbon
OlgaM077 [116]

Answer:

carbon

Explanation:

7 0
3 years ago
Read 2 more answers
The surface charge density on an infinite charged plane is - 2.10 ×10−6C/m2. A proton is shot straight away from the plane at 2.
inn [45]

Explanation:

Formula to calculate electric field because of the plate is as follows.

         E = \frac{\sigma}{2 \times \epsilon_{o}}

            = \frac{2.10 \times 10^{-6}}{2 \times 8.85 \times 10^{-12}}

           = 1.18 \times 10^{5} N/C

Now, we will consider that equilibrium of forces are present there. So,

                   ma = qE

       a = \frac{1.6 \times 10^{-19} \times 1.18 \times 10^{5}}{1.67 \times 10^{-27}}

          = 1.13 \times 10^{13} m/s^2

According to the third equation of motion,

         v^{2} = 2 \times a \times d

or,      d = \frac{v^{2}}{2d}

             = \frac{(2.4 \times 10^{6})^{2}}{2 \times 1.13 \times 10^{13}}

             = 0.254 m

Thus, we can conclude that the proton will travel 0.254 m before reaching its turning point.

7 0
3 years ago
12. An organ pipe that is 1.75 m long and open at both ends produces sound of
podryga [215]

Answer:

354 m/s

Explanation:

For the second overtune (Third harmonic) of an open pipe,

λ = 2L/3................................ Equation 1

Where L = Length of the open pipe, λ = Wave length.

Given: L = 1.75 m.

Substitute into equation 1

λ = 2(1.75)/3

λ = 1.17 m.

From the question,

V = λf.......................... Equation 2

V = speed of sound in the room, f = frequency

Given: f = 303 Hz.

Substitute into equation 2

V = 1.17(303)

V = 353.5

V ≈ 354 m/s

Hence the right answer is 354 m/s

8 0
3 years ago
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