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borishaifa [10]
2 years ago
9

1. The photon energy for light of wavelength 500 nm is approximately (Show your work).

Physics
1 answer:
jeka942 years ago
8 0
1)
E=hf=h*c/α
E=6.626*10^-34*3*10^8E=
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Frequency is the ____________ that move past a point during a specific amount of time. Frequency is measured in ____________ , a
yulyashka [42]

Answer:

Frequency is <u>the number of waves</u> that move past a point during a specific amount of time. Frequency is measured in <u>Hertz</u>, and is classified as high, medium, or low. Frequency is interpreted as the <u>pitch</u> of a sound. Intensity refers to the <u>loudness</u> of a sound and is measured in <u>decibels</u>. Louder sounds <u>increase</u> the rate of nerve signals relayed to the brain.

Explanation:

6 0
3 years ago
After Moseley's discovery in 1913, the periodic law stated that physical and chemical properties tend to repeat periodically whe
stich3 [128]

Answer:

Option B

Explanation:

The correct answer is Option B.

Before Moseley's discovery in 1913, In Mendeleev's periodic table the elements rearranged with increasing atomic mass.

Mendeleev was not able to locate hydrogen atom and late isotopes found violate Mendeleev table. The biggest drawback was that the atomic mass was not regular when moving one element to another.

But Moseley's arranged element in the periodic table with increasing atomic number.  

3 0
3 years ago
Help! (Look in the pic)
hjlf

Answer:

turtle

Explanation:

5 0
2 years ago
A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally
aivan3 [116]

Answer:

option B

Explanation:

given,

height of building = 0.1 km

ball strikes horizontally to ground at = 65 m    

speed at which the ball strike = ?

vertical velocity  = 0 m/s

time at which the ball strike

s = \dfrac{1}{2}gt^2

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 100}{9.8}}

t = 4.53 s

vertical velocity at the time  4.53 s = g × t = 9.8 × 4.53 = 44.39 m/s

horizontal velocity = \dfrac{65}{4.53} =14.35 m/s

speed of the ball = \sqrt{44.39^2+14.35^2}

                             = 46.65 m/s

hence, the speed of the ball just before it strike the ground = 47 m/s

The correct answer is option B

5 0
3 years ago
A cyclical heat engine, operating between temperatures of 450º C and 150º C produces 4.00 MJ of work on a heat transfer of 5.00
gogolik [260]

Answer:

(a) Heat transfer to the environment is: 1 MJ and (b) The efficiency of the engine is: 41.5%

Explanation:

Using the formula that relate heat and work from the thermodynamic theory as:W=Q=Q_{in}-Q_{out} solving to Q_out we get:Q_{out}=Q_{in}-W=5(MJ)-4(MJ)=1(MJ) this is the heat out of the cycle or engine, so it will be heat transfer to the environment. The thermal efficiency of a Carnot cycle gives us: n=1-\frac{T_{Low} }{T_{High}} where T_Low is the lowest cycle temperature and T_High the highest, we need to remember that a Carnot cycle depends only on the absolute temperatures, if you remember the convertion of K=°C+273.15 so T_Low=150+273.15=423.15 K and T_High=450+273.15=723.15K and replacing the values in the equation we get:n=1-\frac{423.15}{723.15} =0.415=41.5%

5 0
3 years ago
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