1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zysi [14]
3 years ago
15

Why are there so few working wave power stations?

Physics
2 answers:
Salsk061 [2.6K]3 years ago
5 0
If you live near a sea or ocean, You Would be getting power. <span>Because the waves are from large bodies of water (sea, ocean ...)</span>
Bond [772]3 years ago
3 0
Well mostly because it's for oceans and lakes that have waves. so if you don't live near any of these, you wouldn't be getting power. <span />
You might be interested in
Which of the following are not vector directions?
Svetradugi [14.3K]

Answer:

here north are not vector option b hope ur help

6 0
3 years ago
Read 2 more answers
A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cr
Musya8 [376]

Answer:

162500000.  

Explanation:

Given that

Diameter of the wire , d= 1.8 mm

The length of the wire ,L = 15 cm

Current ,I = 260 m A

The charge on the electron ,e= 1.6 x 10⁻¹⁹ C

We know that Current I is given as

I=\dfrac{q}{t}

I=Current

q=Charge

t=time

q= I t

q= 260 m t

The total number of electron = n

q= n e

n=\dfrac{260\times 10^{-3}\ t}{1.6\times 10^{-9}}

n=162500000 t

\dfrac{n}{t}=16250000

The number of electron passe per second will be 162500000.

4 0
3 years ago
In a photoelectric experiment, you shine light onto an electrode and record a current of 25 μA. When you apply +500 mV to the el
kkurt [141]

Answer:

2.083 V.

Explanation:

Stopping potential is the potential that is required to stop the current to zero . This potential is applied externally to oppose the potential created by the photoelectric effect . It gives the measure the photoelectric potential being generated .

Here current drops to 25 μA to 19 μA by a potential of 500mV

Change in current

= 25 - 19 = 6 μA

Voltage requirement for unit reduction in current

= 500 / 6 μA

To reduce current 0f 25 μA

requirement of V = (500 / 6 )  x 25 =   2083.33 mV = 2.083 V.

7 0
3 years ago
Dry cells become soft even when not in use. Explain.
mamaluj [8]
This is possible due to self-discharge. Very small internal currents inevitably occur in these cells over time and they will eventually exhaust the chemistry.
4 0
3 years ago
Which one of the following types of electromagnetic wave travels through space the fastest?
Setler [38]

Answer:

As a result, light travels fastest in empty space, and travels slowest in solids. In glass, for example, light travels about 197,000 km/s.

Explanation:

4 0
2 years ago
Other questions:
  • The amount of space between two points is measure in unit?
    11·2 answers
  • The mass number of an atom is equal to ______.
    10·2 answers
  • Based on this activity, is kinetic energy always transformed into potential energy?
    7·2 answers
  • Listening to the radio, you can hear two stations at once. Describe this wave interaction
    12·2 answers
  • Arteriosclerotic plaques forming on the inner walls of arteries can decrease the effective cross-sectional area of an artery. Ev
    5·2 answers
  • A stream of air flowing at 20 liters/min with P = 0.20 MPa and T = 400 K is mixed with a stream ofmethane flowing at 5 liters/mi
    12·1 answer
  • You notice that heat is released during a chemical reaction. This reaction is a(n) _______ reaction. endothermic heat hot exothe
    11·1 answer
  • The whale shark the largest of fish and can have the mass of three adult elephants. Suppose that a crane is whale shark into a t
    5·1 answer
  • Can we make electromagnet with copper​
    12·2 answers
  • Which of the following changes would decrease the force between two charged particles by a factor of 9? A. Decreasing the distan
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!