A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 44.1m/s^2 . The acce
leration period lasts for time 7.00s until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height y_max reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 rm{m/s^2} .
The acceleration and distance is related to the following expression: y=v0*t + a*t^2/2 ; v0=0 y=44.1*100/2 = 2205m hence, the speed will be v=0 + a*t = 441m/s from that height it will just be subjected to the gravitational acceleration 0=v_acc^2 -2g*y_free y_free = v_acc^2/2g = 9922.5m <span>y_max = y_acc+y_free = 441+9922.5 =10363.5m</span>
<span>The initial momentum of the boy is equal to the boy/boat because the final velocity of the boat is less than the initial velocity of the boy.</span>
