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3 years ago

Describe what causes the flow of electric current.

2 answers:

5 0

An electrical current is caused by flow of free electrons from one atom to another.

VMariaS [17]3 years ago

3 0

My answer -

Electrical pressure, called "electro-motive force" (EMF), is what causes current to flow in an electrical circuit. EMF is measured in volts. Pressure and the quantity of electricity transmitted can be considered analogous to pressure and quantity of water flowing in pipes: the longer the distance, the higher is the flow of water (called the "flow of electrical charge, which is also known as the "electric current"). That is why, for long distance transmission, high pressure (voltage for electricity) is required, failing which, the current - and therefore the power - will not reach the intended destination. Instead, it will be lost (also called "dissipate") along the way. We can think of electrical
current as the quantity of electricity which will be drawn from the pipeline
 cables for electricity) at the pressure (= voltage) required. 

P.S

Happy to help you have an AWESOME!!! day ^-^

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A constant force of 45 N directed at angle θ to the horizontal pulls a crate of weight 100 N from one end of a room to another a

Rasek [7]

Answer:

$W=173.48J$

Explanation:

information we know:

Total force: $F=45N$

Weight: $w=100N$

distance: $4m$

vertical component of the force: $F_{y}=12N$

-------------

In this case we need the formulas to calculate the components of the force (because to calculate the work we need the horizontal component of the force).

horizontal component: $F_{x}=Fcos\theta$

vertical component: $F_{y}=Fsen\theta$

but from the given information we know that $F_{y}=12N$

so, equation these two $F_{y}=Fsen\theta$ and $F_{y}=12N$

$Fsen\theta =12N$

and we know the force $F=45N$ , thus:

$45sen\theta=12$

now we clear for $\theta$

$sen\theta =12/45\\\theta=sin^{-1}(12/45)\\\theta =15.466$

the angle to the horizontal is 15.466°, with this information we can calculate the horizontal component of the force:

$F_{x}=Fcos\theta$

$F_{x}=45cos(15.466)\\F_{x}=43.37N$

whith this horizontal component we calculate the work to move the crate a distance of 4 m:

$W=F_{x}*D\\W=(43.37N)(4m)\\W=173.48J$

the work done is W=173.48J

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2 years ago

Which statement about van der Waals forces is true?

kobusy [5.1K]

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3 years ago

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Answer:

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2 years ago

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Answer:

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Answer;

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