Answer:
11.962337 × 10^-4 N
Explanation:
Given the following :
Length L = 11.8
Charge = 29nC = 29 × 10^-9 C
Linear charge density λ = 1.4 × 10^-7 C/m
Radius (r) = 2cm = 2/100 = 0.02 m
Using the relation:
E = 2kλ/r ; F =qE
F = 2kλq/L × ∫dr/r
F = 2*k*q*λ/L × (In(0.02 + L) - In(0.02))
2*k*q*λ/L = [2 × (9 * 10^9) * (29 * 10^9) * (1.4 * 10^-7)]/ 0.118] = 6193.2203 × 10^(9 - 9 - 7) = 6193.2203 × 10^-7 = 6.1932203 × 10^-4
In(0.02 + 0.118) - In(0.02) = In(0.138) - In(0.02) = 1.9315214
Hence,
(6.1932203 × 10^-4) × 1.9315214 = 11.962337 × 10^-4 N
Answer:
It continue to move forward at a constant velocity which will be slower than before the front thruster was fired.
Explanation:
Before the front thruster was fired, the spacecraft was already moving at a particular velocity.
After the malfunction, the front thruster is fired and then the force exerted by that front thruster slows the spacecraft down, as we are told.
By using the rear thruster to exert a force equal to that from the front thrusters, a force equal in magnitude to that of the front thrusters is added, cancelling out the effect of the front thrusters. Because the spacecraft is already moving at a slower speed at this point compared to the beginning, it continues to move at that speed.
Answer:
The angle is 65.6°.
Explanation:
Given that,
Speed = 2.20 m/s
Distance from the shore= 500 m
Distance from the bottom= 1100 m
Speed of boat = 7.30 m/s
According to figure,
We need to calculate the angle with shore
Using formula of angle

Put the value into the formula



We need to calculate the angle

Put the value into the formula


Hence, The angle is 65.6°.
The total distance traveled by the car at the given velocity and time is 900 m.
The given parameters:
- <em>initial velocity of the car, u = 20 m/s</em>
- <em>acceleration of the car, a = 12 m/s²</em>
- <em>time of motion of the car, t = 20 s</em>
- <em>final time = 30 s</em>
- <em>final acceleration = 2 m/s²</em>
The final time of motion of car before coming to rest is calculated as follows;

The graph of the car's motion is in the image uploaded.
The total distance traveled by the car is calculated as follows;

Thus, the total distance traveled by the car at the given velocity and time is 900 m.
Learn more about velocity-time graph here: brainly.com/question/24874645