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notsponge [240]
4 years ago
13

Describe what causes the flow of electric current.

Physics
2 answers:
marusya05 [52]4 years ago
5 0
An electrical <span>current is </span>caused<span> by </span>flow<span> of free electrons from one atom to another. </span>
VMariaS [17]4 years ago
3 0
My answer -

Electrical pressure, called "electro-motive force" (EMF), is what causes current <span>to flow in an electrical circuit. EMF is measured in volts. Pressure and the </span><span>quantity of electricity transmitted can be considered analogous to pressure and </span><span>quantity of water flowing in pipes: the longer the distance, the higher is the </span><span>flow of water (called the "flow of electrical charge, which is also known as the </span><span>"electric current"). That is why, for long distance transmission, high pressure </span><span>(voltage for electricity) is required, failing which, the current - and </span><span>therefore the power - will not reach the intended destination. Instead, it will </span><span>be lost (also called "dissipate") along the way. We can think of electrical
 </span><span>current as the quantity of electricity which will be drawn from the pipeline
</span><span> cables for electricity) at the pressure (= voltage) required. </span>


P.S

Happy to help you have an AWESOME!!! day ^-^










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2. At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (nautical miles per hour; a n
AleksandrR [38]

Answer:

No

Explanation:

Let the reference origin be location of ship B in the beginning. We can then create the equation of motion for ship A and ship B in term of time t (hour):

A = 12 - 12t

B = 9t

Since the 2 ship motions are perpendicular with each other, we can calculate the distance between 2 ships in term of t

d = \sqrt{A^2 + B^2} = \sqrt{(12 - 12t)^2 + (9t)^2}

For the ships to sight each other, distance must be 5 or smaller

d \leq 5

\sqrt{(12 - 12t)^2 + (9t)^2} \leq 5

(12 - 12t)^2 + (9t)^2 \leq 25

144t^2 - 288t + 144 + 81t^2 - 25 \leq 0

225t^2 - 288t + 119 \leq 0

(15t)^2 - (2*15*9.6)t + 9.6^2 + 26.84 \leq 0

(15t^2 - 9.6)^2 + 26.84 \leq 0

Since (15t^2 - 9.6)^2 \geq 0 then

(15t^2 - 9.6)^2 + 26.84 > 0

So our equation has no solution, the answer is no, the 2 ships never sight each other.

8 0
3 years ago
How does a sound wave's amplitude affect the sound we hear? How does a sound
damaskus [11]

Answer:

cause we hear differently

Explanation:

7 0
3 years ago
Read 2 more answers
Please help anyone i will mark brainliest
Andrei [34K]
Fg = G m₁ m₂ / r²

Fg = (6.67×10−¹¹) ( 70) ( 5.972×10²⁴) / (6.3781×10⁶)²

Fg = 685.43 N
4 0
3 years ago
When you rub your hands together, you cannot push harder on one hand than the other. can push harder on one hand than the other.
Sholpan [36]
I think it means that your putting in an equal amount of force on each hand because it's the same brain that controls what you do. I think that's what it means, not entirely sure but hope this helps
3 0
3 years ago
Calculate the escape speed for a spacecraft from the surface of (a) mars; and from the surface of (b) jupiter. ( the escape spee
Len [333]
The escape speed for a spacecraft at the surface of a planet of mass M and radius R is:
v= \sqrt{ \frac{2GM}{R} }
where G is the gravitational constant. We can use this formula to solve both parts of the problem, using the data of Jupiter and Mars.

a) Mars:
Mars mass is M=6.4 \cdot 10^{24}kg, while Mars radius is R=3.4 \cdot 10^6 m, so the escape speed of the spacecraft at Mars surface is
v= \sqrt{ \frac{2 (6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(6.4 \cdot 10^{24} kg)}{3.4 \cdot 10^6 m} }= 5011 m/s = 5.01 km/s

b) Jupiter:
Jupiter mass is M=1.9 \cdot 10^{27} kg while its radius is R=7.15 \cdot 10^7 m, so the escape speed at its surface is
v= \sqrt{ \frac{2 (6.67 \cdot 10^{-11} m^3 kg^{-1}s^{-2})(1.9 \cdot 10^{27} kg)}{7.15 \cdot 10^7 m} }=5.95 \cdot 10^4 m/s = 59.5 km/s

3 0
3 years ago
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