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valina [46]
2 years ago
5

consider the hypothetical observation irregular galaxies outside the local group are moving toward us. from part a, this observa

tion would contradict the idea of an expanding universe. why?
Physics
1 answer:
alina1380 [7]2 years ago
3 0

Answer:

spiral galaxies move away from us 10% faster than elliptical galaxies at the same distances;  irregular galaxies outside the Local Group are moving toward us;  galaxy speeds are faster in summer than in winter

Explanation:

This may help I'm not sure.

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In a given chemical reaction the energy of the products is less than the energy of the reactants. Which statement is true for th
Westkost [7]

Answer:

B. Energy is released in the reaction.

7 0
3 years ago
The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in m
BARSIC [14]

A) The resultant force is 30.4 N at 25.3^{\circ}

B) The resultant force is 18.7 N at 43.9^{\circ}

Explanation:

A)

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

The two forces are:

F_1 = 20 N at 0^{\circ} above x-axis

F_2 = 15 N at 60^{\circ} above y-axis

Resolving each force:

F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N

F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N

So, the components of the resultant are:

F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N

And the magnitude of the resultant is:

F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N

And the direction is:

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}

B)

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

\theta=180^{\circ}-60^{\circ}=120^{\circ}

So we have:

F_{2x}=F_2 cos \theta = (15)(cos 120)=-7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 120)=13.0 N

So, the components of the resultant this time are:

F_x = F_{1x}+F_{2x}=20-7.5 = 12.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N

And the magnitude is:

F=\sqrt{F_x^2+F_y^2}=\sqrt{13.5^2+13.0^2}=18.7 N

And the direction is:

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{13.5})=43.9^{\circ}

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

7 0
3 years ago
What is terrestrial radiation?
Feliz [49]
C) Radiation that comes from Earth...... Hope it helps, Have a nice day :)
6 0
3 years ago
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A geologist is comparing the properties of different minerals. He rubs each one on a piece of white tile and observes the color
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He performed a streak test, in which a piece of the mineral is rubbed across a piece of unglazed porcelain in order to determine the color of the mineral in powdered form.

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3 years ago
Bx = -1.33 m and By = 2.81 m<br> Find the magnitude of the<br> vector.
NISA [10]

Answer:

Explanation:

The formula for the magnitude of a vector is

B_{mag}=\sqrt{(-1.33)^2+(2.81)^2} and then round to the hundredths place:

3.11 m. Since we are in Q2, we can also find the direction of this vector:

tan^{-1}(\frac{2.81}{-1.33})=-64.7 but since we are in Q2, we add 180 degrees to the result, getting the angle to be 115.3

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3 years ago
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