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Pavel [41]
4 years ago
13

Which materials, including polystyrenes, can be recycled?

Physics
2 answers:
True [87]4 years ago
4 0
Polymers as they are made from plastic
Oksanka [162]4 years ago
4 0

Answer:

Polymers , thermoplastics.

Explanation:

Polymers like thermoplastic polymers can be recycled because they can be melted easily but thermosetting polymer can not be recycled because of their high melting point. Ceramics due to their high melting point are not recycled.

Thermoplastic composites can be recycled but thermoseting composites are not recycled. Composites are mix of two or more type of material having different physical and chemical properties.

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A car moving at 10.0 m/s encounters a depression in the road that has a circular cross-section with a radius of 30.0 m. What is
Dennis_Churaev [7]

Answer:

F = 789 Newton

Explanation:

Given that,

Speed of the car, v = 10 m/s

Radius of circular path, r = 30 m

Mass of the passenger, m = 60 kg

To find :

The normal force exerted by the seat of the car when the it is at the bottom of the depression.

Solution,

Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.

N=mg+\dfrac{mv^2}{r}

N=m(g+\dfrac{v^2}{r})

N=60\times (9.81+\dfrac{(10)^2}{30})

N = 788.6 Newton

N = 789 Newton

So, the normal force exerted by the seat of the car is 789 Newton.

6 0
3 years ago
Technician A says when diagnosing an overheating hydraulic system, be sure that the oil cooler is not plugged and the cooler’s f
mel-nik [20]

Answer:

Tech B is correct and Tech A is incorrect.

Explanation:

Here Tech A is wrong because when diagnosing an overheating hydraulic system, it is not necessary to un plugg the oil cooler rather it should be plugged to for proper diagnosis.

Technician B says running the hydraulic system at a lower operating temperature will reduce the possibly of oil oxidation is correct statement because at temperature oil's physical as well as chemical property tend to change.

Hence, Tech B is correct and Tech A is incorrect.

8 0
3 years ago
The perihelion of the comet TOTAS is 1.69 AU and the aphelion is 4.40 AU. Given that its speed at perihelion is 28 km/s, what is
dybincka [34]

Answer:

The speed at the aphelion is 10.75 km/s.

Explanation:

The angular momentum is defined as:

L = mrv (1)

Since there is no torque acting on the system, it can be expressed in the following way:

t = \frac{\Delta L}{\Delta t}

t \Delta t = \Delta L

\Delta L = 0

L_{a} - L_{p} = 0

L_{a} = L_{p}   (2)

Replacing equation 1 in equation 2 it is gotten:

mr_{a}v_{a} =mr_{p}v_{p} (3)

Where m is the mass of the comet, r_{a} is the orbital radius at the aphelion, v_{a} is the speed at the aphelion, r_{p} is the orbital radius at the perihelion and v_{p} is the speed at the perihelion.          

From equation 3 v_{a} will be isolated:    

v_{a} = \frac{mr_{p}v_{p}}{mr_{a}}

v_{a} = \frac{r_{p}v_{p}}{r_{a}}   (4)    

Before replacing all the values in equation 4 it is necessary to express the orbital radius for the perihelion and the aphelion from AU (astronomical units) to meters, and then from meters to kilometers:

r_{p} = 1.69 AU x \frac{1.496x10^{11} m}{1 AU} ⇒ 2.528x10^{11} m

r_{p} = 2.528x10^{11} m x \frac{1km}{1000m} ⇒ 252800000 km

r_{a} = 4.40 AU x \frac{1.496x10^{11} m}{1 AU} ⇒ 6.582x10^{11} m

r_{p} = 6.582x10^{11} m x \frac{1km}{1000m} ⇒ 658200000 km  

     

Then, finally equation 4 can be used:

v_{a} = \frac{(252800000 km)(28 km/s)}{(658200000 km)}

v_{a} = 10.75 km/s

Hence, the speed at the aphelion is 10.75 km/s.

       

8 0
3 years ago
A ladder placed up against a wall is sliding down. The distance between the top of the ladder and the foot of the wall is decrea
Kitty [74]

Answer:

distance changing at rate of 3.94 inches/sec

Explanation:

Given data

wall decreasing at a rate = 9 inches per second

ladder L = 152 inches

distance  h = 61 inches

to find out

how fast is the distance changing

solution

we know that

h² + b² = L²   ..................1

h² + b² = 152²

Apply here derivative w.r.t. time

2h dh/dt + 2b db/dt = 0

h dh/dt + b db/dt = 0

db/dt = - h/b × dh/dt     .............2

and

we know

h = 61

so h² + b² = L²

61² + b² = 152²

b² = 19383

so b = 139.223

and we know dh/dt = -9 inch/sec

so from equation 2

db/dt = -61/139.223  (-9)

so

db/dt = 3.94 inches/sec

distance changing at rate of 3.94 inches/sec

3 0
4 years ago
A rock is suspended from a string, and it accelerates downward. Which one of the following statements is correct? Group of answe
Tems11 [23]

Answer:

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

Explanation:

During the motion of the rock while it is in downward motion we can say

T - mg cos\theta = ma_c

since it is performing circular motion so we will have its acceleration towards its center

T = mgcos\theta + ma_c

a_c = \frac{v^2}{L}

T = mgcos\theta + \frac{mv^2}{L}

So at the lowest point of the path we can say

T = mg + \frac{mv^2}{L}

so correct answer is

a. The magnitude of the tension in the string is greater than the magnitude of the weight of the rock.

4 0
3 years ago
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