A square conducting plate 52.0 cm on a side and with no net charge is placed in a region, where there is a uniform electric fiel
1 answer:
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Answer:
Explanation:
The dot product of two vectors and
is given by
The dot product of two orthogonal vector is always zero thus if and
, their dot product would be
Answer:
If the cart is being pushed at a constant speed, then the acceleration in the direction of motion is zero. Hence, the force in the direction of the motion is zero, according to Newton's Second Law.
For simplicity, I will denote the direction along the inclined ramp as x-direction.
In the question the value of the force is not clearly given, so I will denote it as
Here the angle between the applied force and the x-direction is 12° + 17° = 29°
The x-component of the weight of the cart is equal to sine component of the weight.
Since the cart is rolling on tires the kinetic friction does no work.
Work done by the applied force:
Work done by the weight of the cart:
Since the x-component of the weight is in the -x-direction, its work is negative.
Conveniently, the total work done on the particle is zero, since its velocity is constant.
Answer:
v_{4}= 80.92[m/s] (Heading south)
Explanation:
In order to calculate this problem, we must use the linear moment conservation principle, which tells us that the linear moment is conserved before and after the collision. In this way, we can propose an equation for the solution of the unknown.
ΣPbefore = ΣPafter
where:
P = linear momentum [kg*m/s]
Let's take the southward movement as negative and the northward movement as positive.
where:
m₁ = mass of car 1 = 14650 [kg]
v₁ = velocity of car 1 = 18 [m/s]
m₂ = mass of car 2 = 3825 [kg]
v₂ = velocity of car 2 = 11 [m/s]
v₃ = velocity of car 1 after the collison = 6 [m/s]
v₄ = velocity of car 2 after the collision [m/s]