Answer:
C. 98 J
Explanation:
The appropriate formula is ...
PE = mgh . . . . . m is mass; below, m is meters
PE = (5 kg)(9.8 m/s^2)(2 m) = 98 kg·m^2/s^2
PE = 98 J
Answer:
The total number of significant figures is twelve.
Explanation:
Answer:
i think it would be Galvanometer
Explanation:
because it would have to be a type of coil or wire
Answer:
Given that
The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days)
a)
When earth spins on its axis
We know that earth take 1 day to complete one revolution around its own axis.
T= 1 day = 24 hr = 24 x 3600 s
T=86400 s
We know that
T=2π/ω
ω= 2π/T
ω= 2π/86400
ω=7.27 x 10⁻5 rad/s
b)
When earth revolve around earth
T =365 1/4 days = 365.25 days
T= 365.24 x 86400 s
T=31557600
We know that
T=2π/ω
ω= 2π/T
ω= 2π/31557600
ω=1.99 x 10⁻⁷ rad/s
What happens to end a of the rod when the ball approaches it closely this first time is; It is strongly attracted.
<h3>Electrostatics</h3>
I have attached the image of the rod.
We are told that the ball is much closer to the end of the rod than the length of the rod. Thus, if we point down the rod several times, the distance of approach will experience no electric field and as such the charge on end point A of the rod must be comparable in magnitude to the charge on the ball.
This means that their fields will cancel.
Finally, we can conclude that when a charge is brought close to a conductor, the opposite charges will all navigate to the point that is closest to the charge and as a result, a strong attraction will be created.
This also applies to a strong conducting rod and therefore it is strongly attracted.
Read more about Electrostatics at; brainly.com/question/18108470