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kodGreya [7K]
3 years ago
8

A square conducting plate 52.0 cm on a side and with no net charge is placed in a region, where there is a uniform electric fiel

d of 82.0 kN/C directed to the right and perpendicular to the plate.
Find
(a) the charge density of each face of the plate and
(b) the total charge on each face.
Physics
1 answer:
Mrac [35]3 years ago
5 0

Explanation:

Given:  uniform electric field E= 82.0 kN/C.

a) charge density σ =ε_0 E.

therefore, \sigma =82\times10^3\times3.85\times10^{-12}\\=0.0000003157= 315.7 nC/m^2

b)Total charge on each face = σA

q=σA

=315.7\times10^{-9}\times52\times10^{-4}\\=1.614\times10^{-9}= 1.614 \text{ nC}\\\text{Similarly on the other face }  = -1.614 \text{ nC}

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7 0
3 years ago
When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displ
Ray Of Light [21]

Answer:

period of oscillations is 0.695 second

Explanation:

given data

mass m = 0.350 kg

spring stretches x = 12 cm = 0.12 m

to find out

period of oscillations

solution

we know here that force

force = k × x   .........1

so force = mg =  0.35 (9.8)  = 3.43 N

3.43 = k × 0.12

k = 28.58 N/m

so period of oscillations is

period of oscillations = 2π × \sqrt{\frac{m}{k} }   ................2

put here value

period of oscillations = 2π × \sqrt{\frac{0.35}{28.58} }  

period of oscillations = 0.6953

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4 0
3 years ago
Consider a large tank holding 1000 L of pure water into which a brine solution of salt begins to owat a constant rate of 6L/min.
lbvjy [14]

Answer:

T = 693.147 minutes

Explanation:

The tank is being continuously stirred. So let the salt concentration of the tank at some time t be x in units of kg/L.

Therefore, the total salt in the tank at time t = 1000x kg

Brine water flows into the tank at a rate of 6 L/min which has a concentration of 0.1 kg/L

Hence, the amount of salt that is added to the tank per minute = (6\times0.1)kg/min=0.6kg/min

Also, there is a continuous outflow from the tank at a rate of 6 L/min.

Hence, amount of salt subtracted from the tank per minute = 6x kg/min

Now, the rate of change of salt concentration in the tank = \frac{dx}{dt}

So, the rate of change of salt in the tank can be given by the following equation,

1000\frac{dx}{dt} =0.6-6x

or, \int\limits^{0.05}_0 {\frac{1000}{0.6-6x} } \, dx =\int\limits^T_0 {} \, dt

or, T = 693.147 min      (time taken for the tank to reach a salt concentration

of 0.05 kg/L)

3 0
3 years ago
An object is 2.0 m in front of a plane mirror. Its image is:?
maria [59]
Planes don’t have mirrors
6 0
3 years ago
A ball is projected vertically upward from the surface of the Earth with an initial speed of +49 meters per second. The ball rea
fenix001 [56]
Answer: 245 meters

Explanation: 49 ? Meters
over over over
1 5 seconds

Cross multiply- 49 times 5 divided by 1 which equals 245
8 0
3 years ago
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