Nerve cells transmit electrical signals through their long tubular axons. These signals propagate due to a sudden rush of Na+ io
ns, each with charge +e, into the axon. Measurements have revealed that typically about 6.2×1011 Na+ ions enter each meter of the axon during a time of 13 ms.
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Answer:
d= 0.48 m
Explanation:
Given that
time ,t= 40 m s= 40 x 10⁻³ s
Constant acceleration ,a= - 60 g
We know that g= 10 m/s²
Therefore ,a=- 60 x 10 =- 600 m/s²
We know that
v= u + a t
u=initial speed
v=final sped
t=time
a=acceleration
Now by putting the value
0 = u - 600 x 40 x 10⁻³
u = 24 m/s
The distance cover before coming to stop d is given as
d= 0.48 m
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