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Snowcat [4.5K]
3 years ago
5

Which statement BEST describes the benefits of muscular fitness training?

Physics
1 answer:
Hoochie [10]3 years ago
6 0
I think it is A <span>High levels of muscular fitness can improve your self-image and improve or prevent chronic diseases such as diabetes, osteoporosis, and cardiovascular disease.</span>
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Aunt Matilda goes to a well and throws a penny straight down the well at 3.0 m/s. She hears a splash after 0.5 seconds. How deep
nevsk [136]

Answer : The correct option is (d) 2.73 m

Explanation :

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2

where,

s = distance or height = ?

u = initial velocity  = 3.0 m/s

t = time = 0.5 s

a = acceleration due to gravity = 9.8m/s^2

Now put all the given values in the above equation, we get:

s=(3.0m/s)\times (0.5s)+\frac{1}{2}\times (9.8m/s^2)\times (0.5s)^2

s=2.73m

Therefore, the correct option is (d) 2.73 m

8 0
3 years ago
One student bangs two bricks together
Romashka-Z-Leto [24]

Answer:

This could be done if a stop watch is used to calculate the time taken to hear the echo and a rule should be used to calculate the distance between the bricks and the wall. Then divide distance by time

Explanation:

I hope this is what you need

PLEASE MAKE ME BRAINLIEST

7 0
3 years ago
These two pls :)))) ill mark brainliest :)
Anna71 [15]

Answer:

Bowling Ball: weight on Earth = 49 N

Textbook: Mass = 2 kg; weight on the moon = 3.2 N

Large dog: weight on Earth = 490 N; weight on the moon = 80 N

Law of Universal Gravitation: F_{G}=\frac{Gm_{1}m_{2}}{r^{2}}

F_{G} = gravitational force (Newtons/N)

<em>G</em> = gravitational constant, 6.67430 × 10¹¹ \frac{N*m^{2}}{kg^{2}}

<em>m</em>₁ and <em>m</em>₂ = masses of two objects (kilograms/kg)

<em>r</em>² = square of distance between centers of the two objects (meters/m)

Have a fantastic day!

4 0
2 years ago
Why is a neutral object attracted to a charged object?
mixas84 [53]
Because electricity attracts like people
7 0
3 years ago
A projectile lands at the same height from which it was launched. which initial velocity will result
Serhud [2]

The required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

First, we must understand that the component of the velocity along the vertical is due to maximum height achieved and expressed as usin θ.

The component of the velocity along the horizontal is due to the range of the object and is expressed as ucosθ.

If the <u>air resistance is ignored</u>, the velocity of the object will be constant throughout the flight and the initial velocity will be equal to the final velocity.

Hence the required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

Learn more here; brainly.com/question/12870645

5 0
3 years ago
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