Which of the following results from the fact that skip signals refracted from the ionosphere are elliptically polarized?

Sasha goes back through her architectural design books for inspiration and designs the new country club to have a Romanesque fee

vfiekz [6]

She should create a computer animated view of the design to walk the client through it so that client will understand and get the picture of the design.

3 0

3 years ago

The speed of sound is 1150 ft/s convert to mile/h

Sonbull [250]

Answer:

784.090909mph

Explanation:

1ft/s=0.681818 mph

1150ft/s=0.681818 x 1150=784.090909

6 0

3 years ago

The ABC Corporation manufactures and sells two products: T1 and T2. 20XX budget for the company is given below:

Sliva [168]

Answer:

The ABC Corporation

a) Total Expected Revenue (in dollars) for 20XX:

Revenue from T1 = 60,000 x $165 = $26,400,000

Revenue from T2 = 40,000 x $250 = $10,000,000

Total Revenue from T1 and T2 = $36,400,000

b) Production Level (in units) for T1 and T2

T1 T2

Total Units sold 160,000 40,000

Add Closing Inventory 25,000 9,000

Units Available for sale 185,000 49,000

less opening inventory 20,000 8,000

Production Level 165,000 units 41,000 units

c) Total Direct Material Purchases (in dollars):

Cost of direct materials used T1 T2

A: (165,000 x 4 x $12) $7,920,000 $2,460,000 (41,000 x 5 x $12)

B: (165,000 x 2 x $5) 1,650,000 615,000 (41,000 x 3 x $5)

C: 0 123,000 (41,000 x 1 x$3)

Total cost $9,570,000 $3,198,000 Total = $12,768,000

Cost of direct per unit = $58 ($9,570,000/165,000) for T1 and $78 ($3,198,000/41,000) for T2

Cost of direct materials used for production $12,768,000

Cost of closing direct materials:

A (36,000 x $12) $432,000

B (32,000 x $5) 160,000

C (7,000 x $3) 21,000 $613,000

Cost of direct materials available for prodn $13,381,000

Less cost of beginning direct materials:

A (32,000 x $12) $384,000

B (29,000 x $5) 145,000

C (6,000 x $3) 18,000 $547,000

Cost of direct materials purchases $12,834,000

d) The Total Direct Manufacturing Labor Cost (in dollars):

T1 T2

Direct labor per unit 2 hours 3 hours

Direct labor rate per hour $12 $16

Direct labor cost per unit $24 $48

Production level 165,000 units 41,000 units

Labor Cost ($) $3,960,000 $1,968,000

Total labor cost $5,928,000 ($3,960,000 + $1,968,000)

e) Total Overhead cost (in dollars):

Overhead rate = $20 per labor hour

Overhead cost per unit: T1 = $40 ($20 x 2) and T2 = $60 ($20 x 3)

T1 overhead = $20 x 2 x 165,000) = $6,600,000

T2 overhead = $20 x 3 x 41,000) = $2,460,000

Total Overhead cost = $9,060,000

Cost of goods produced:

Cost of opening inventory of materials = $547,000

Purchases of directials materials 12,834,000

less closing inventory of materials = $613,000

Cost of materials used for production 12,768,000

add Labor cost 5,928,000

add Overhead cost 9,060,000

Total production cost $27,756,000

f) Total cost of goods sold (in dollars):

Cost of opening inventory = $3,928,000

Total Production cost = $27,756,000

Cost of goods available for sale $31,684,000

Less cost of closing inventory $4,724,000

Total cost of goods sold $26,960,000

g) Total expected operating income (in dollars)

Sales Revenue: T1 and T2 $36,400,000

Cost of goods sold 26,960,000

Gross profit $9,440,000

less marketing & distribution 400,000

Total Expected Operating Income = $9,040,000

Explanation:

a) Cost of beginning inventory of finished goods:

T1, (Direct materials + Labor + Overhead) X inventory units =

T1 = 20,000 x ($58 + 24 + 40) = $2,440,000

T2 = 8,000 ($78 + 48 + 60) = $1,488,000

Total cost of beginning inventory = $3,928,000

b) Cost of closing Inventory of finished goods:

T1 = 25,000 x ($58 + 24 + 40) = $3,050,000

T2 = 9,000 ($78 + 48 + 60) = $1,674,000

Total cost of closing inventory = $4,724,000

5 0

4 years ago

A hollow steel tube with an inside diameter of 100 mm must carry a tensile load of 400 kN. Determine the outside diameter of the

Olegator [25]

Answer:

119.35 mm

Explanation:

Given:

Inside diameter, d = 100 mm

Tensile load, P = 400 kN

Stress = 120 MPa

let the outside diameter be 'D'

Now,

Stress is given as:

stress = Load × Area

also,

Area of hollow pipe = $\frac{\pi}{4}(D^2-d^2)$

or

Area of hollow pipe = $\frac{\pi}{4}(D^2-100^2)$

thus,

400 × 10³ N = 120 × $\frac{\pi}{4}(D^2-100^2)$

or

D² = tex]\frac{400\times10^3+30\pi\times10^4}{30\pi}[/tex]

or

D = 119.35 mm

7 0

3 years ago

Read 2 more answers

A piston-cylinder device contains 0.1 m3 of liquid water and 0.9 m² of water vapor in equilibrium at 800 kPa. Heat is transferre

docker41 [41]

Answer:

Initial temperature = 170. 414 °C

Total mass = 94.478 Kg

Final volumen = 33.1181 m^3

Diagram = see picture.

Explanation:

We can consider this system as a close system, because there is not information about any output or input of water, so the mass in the system is constant.

The information tells us that the system is in equilibrium with two phases: liquid and steam. When a system is a two phases region (equilibrium) the temperature and pressure keep constant until the change is completed (either condensation or evaporation). Since we know that we are in a two-phase region and we know the pressure of the system, we can check the thermodynamics tables to know the temperature, because there is a unique temperature in which with this pressure (800 kPa) the system can be in two-phases region (reach the equilibrium condition).

For water in equilibrium at 800 kPa the temperature of saturation is 170.414 °C which is the initial temperature of the system.

to calculate the total mass of the system, we need to estimate the mass of steam and liquid water and add them. To get these values we use the specific volume for both, liquid and steam for the initial condition. We can get them from the thermodynamics tables.

For the condition of 800 kPa and 170.414 °C using the thermodynamics tables we get:

Vg (Specific Volume of Saturated Steam) = 0.240328 m^3/kg

Vf (Specific Volume of Saturated Liquid) = 0.00111479 m^3/kg

if you divide the volume of liquid and steam provided in the statement by the specific volume of saturated liquid and steam, we can obtain the value of mass of vapor and liquid in the system.

Steam mass = *0.9 m^3 / 0.240328 m^3/kg = 3.74488 Kg

Liquid mass = 0.1 m^3 /0.00111479 m^3/kg = 89.70299 Kg

Total mass of the system = 3.74488 Kg + 89.70299 Kg = 93,4478 Kg

If we keep the pressure constant increasing the temperature the system will experience a phase-change (see the diagram) going from two-phase region to superheated steam. When we check for properties for the condition of P= 800 kPa and T= 350°C we see that is in the region of superheated steam, so we don’t have liquid water in this condition.

If we want to get the final volume of the water (steam) in the system, we need to get the specific volume for this condition from the thermodynamics tables.

Specific Volume of Superheated Steam at 800 kPa and 350°C = 0.354411 m^3/kg

We already know that this a close system so the mass in it keeps constant during the process.

If we multiply the mass of the system by the specific volume in the final condition, we can get the final volume for the system.

Final volume = 93.4478 Kg * 0.354411 m^3/kg = 33.1189 m^3

You can the P-v diagram for this system in the picture.

For the initial condition you can calculate the quality of the steam (measure of the proportion of steam on the mixture) to see how far the point is from for the condition on all the mix is steam. Is a value between 0 and 1, where 0 is saturated liquid and 1 is saturated steam.

Quality of steam = mass of steam / total mass of the system

Quality of steam = 3.74488 Kg /93.4478 Kg = 0,040 this value is usually present as a percentage so is 4%.

Since this a low value we can say that we are very close the saturated liquid point in the diagram.

6 0

4 years ago