<u>Answer:</u> Oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.
<u>Explanation:</u>
We are given a compound having formula
and we need to find the oxidation state of all the atoms in this compound. There are 2 different atoms present in this : Arsenic and Oxygen
Oxidation state is the number which is assigned to an element in a compound which represents the number of electrons lost or gained by an atom in a compound.
Oxidation state of oxygen as -2 which is same always. Now, to calculate the oxidation state of Arsenic, we take the oxidation state of it be 'x'
As, there are two arsenic atoms and three oxygen atoms, then:

Hence, oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.
Answer:
N2 (but the 2 is a subscript) i think
Explanation:
i looked it up
The core of an atom contains protons and neutrons.
The first thing to do is to convert the mass of sodium
sulfate to moles. Since the given is in milligrams convert it to grams which
would be 0.02824 grams. The number of moles can be calculated by dividing the
converted weight with the given molar mass which is 139.04 g/mol. The number of
mols in the solution is 2.03x10^-4 mols. Then divide the number of moles with
0.02355 L. The molarity of the solution is 0.00862 M.