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3 years ago

The table shows the outputs y for different inputs x:

1 answer:

4 0

Part A: yes, because every input value x produces only one output value y.

Part B: in the first function, when x=7, why=8 is given
in the second function, when x=7, y=2x+13=27
so the second function has a greater value when x=7

Part C: when f(x)=2x+13=75, 2x=62, x=31

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The perimeter of a triangle is 40 inches. The middle length side is twice as long as the short

creativ13 [48]

Answer:

Step-by-step explanation:

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3 years ago

Given m||n, find the value of x.<br> t<br> (7x-1)<br> (8x-14)

devlian [24]

Step-by-step explanation:

7x-1=8x-14

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3 years ago

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A survey has a margin error of +/– 5%. In the survey, 91 out of 100 people said that they were pleased with their phone service.

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3 years ago

the fifth grade class has made paper chains for a Fall Festival each chains they made was 5ft 8in long how many inches long was

Igoryamba

Answer:

68 inches

Step-by-step explanation:

The chains are 5ft and 8 inches long.

Your answer must be in inches, so convert any non-inch units to inches.

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3 years ago

Please check my homework on Negative Indices!

rusak2 [61]

Our first expression is $(2p^{-3} q^{8} )^{4}$ . Upon distributing the exponent 4 on all the terms, we get:

$(2p^{-3} q^{8} )^{4}=2^{4}(p^{-3})^{4}(q^{8})^{4}=16p^{-12}q^{32}=\frac{16q^{32}}{p^{12}}$

Therefore, your answer is correct for this part. :)

Second expression is $(2m^{-4}n^{5})^{-2}$ . Upon distributing the exponent -2 on all the terms, we get:

$(2m^{-4}n^{5})^{-2}=2^{-2}(m^{-4})^{-2}(n^{5})^{-2}=2^{-2}m^{8}n^{-10}=\frac{m^{8}}{4n^{10}}$

Your second answer is correct too.

Our third expression is $2(5g^{-4}h^{-6})^{2}$ . Upon distributing the exponent 2 on all the terms, we get:

$2(5g^{-4}h^{-6})^{2}=2(5^{2})(g^{-4})^{2}(h^{-6})^{2}=2(25)g^{-8}h^{-12}=\frac{50}{g^{8}h^{12}}$

This one is not correct. Your answer would have been correct, if the exponent were -2 instead of 2 in this part.

Our forth and last expression is $4(2c^{-3}d^{6})^{-5}$ . Upon distributing the exponent -5 on all the terms inside the parenthesis, we get:

$4(2c^{-3}d^{6})^{-5}=4(2^{-5})(c^{-3})^{-5}(d^{6})^{-5}=\frac{4}{2^{5}}(c^{15})(d^{-30})=\frac{4c^{15}}{32d^{30}}=\frac{c^{15}}{8d^{30}}$

Therefore, your answer for this part is also correct.

Looking at your work, I don't think you made a mistake in number 3 also, probably mis-typed the question while writing here :)

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4 years ago