Answer:
i) 796.18 N/mm^2
ii) 1111.11 N/mm^2
Explanation:
Initial diameter ( D ) = 12 mm
Gage Length = 50 mm
maximum load ( P ) = 90 KN
Fractures at = 70 KN
minimum diameter at fracture = 10mm
<u>Calculate the engineering stress at Maximum load and the True fracture stress</u>
<em>i) Engineering stress at maximum load = P/ A </em>
= P / = 90 * 10^3 / ( 3.14 * 12^2 ) / 4
= 90,000 / 113.04 = 796.18 N/mm^2
<em>ii) True Fracture stress = P/A </em>
= 90 * 10^3 / ( 3.24 * 10^2) / 4
= 90000 / 81 = 1111.11 N/mm^2
Answer:
A) 2P/(¶r^2)
B) p/(¶r^2)
Explanation:
Force = P
Radius = r
Area on which force acts = ¶r^2
If both forces are applied, total stress will be
S = 2P/(¶r^2)
When only one of the force is applied
S = p/(¶r^2)
Answer:
2.379m
Explanation:
The width = 23m
The depth = 3m
The radius is denoted as R
The wetted area is = A
The perimeter perimeter = P
Hydraulic radius
R = A/P
The area of a rectangular channel
= Width multiplied by Depth
A = 23x3
A = 69m²
Perimeter = (2x3)+23
P = 6+23
P= 29
Hydraulic radius R = 69/29
= 2.379m
This answers the question
Thank you!
Answer:
A. Vo = -0.606 volts
B. Vo = -0.349 volts
Explanation:
In this question, we are asked to calculate the output voltage by analyzing the conditions given and also calculate the output voltage given that one of theses conditions changed.
Please check attachment for complete solution.