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Dahasolnce [82]
3 years ago
6

Compared to visible light, an electromagnetic wave that has a higher wavelength will also have ________.

Chemistry
2 answers:
sp2606 [1]3 years ago
7 0

Compared to visible light, an electromagnetic wave that has a higher wavelength will also have <u>a lower frequency</u>.

That's because frequency and wavelength are inversely related.

f ∝ 1/λ

When one goes up, the other goes down and <em>vice vesa</em>.

nadezda [96]3 years ago
7 0

<u>Answer:</u> The correct answer is lower frequency.

<u>Explanation:</u>

Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light.

Visible light is also an electromagnetic wave.

The relationship between wavelength and frequency of the wave follows the equation:

\nu=\frac{c}{\lambda}

where,

\nu = frequency of the wave

c = speed of light

\lambda = wavelength of the wave

From the above relation, it is visible that wavelength and frequency follow inverse relation. For increase in wavelength, the value of frequency decreases and vice-versa.

Thus, for higher wavelength, the electromagnetic wave will also have lower frequency.

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Explanation:

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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
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Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

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Partial co-efficient (K) = \frac{C_1}{C_2}

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4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

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2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

B = \frac{0.6}{3.76}

B = 0.159 g

B = 159 mg

∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

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