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3 years ago

PLEASE SOMEONE HELP ME WITH THIS

Chemistry

1 answer:

Likurg_2 [28]3 years ago

3 0

Answer:

1.30 moles

Explanation:

As written, the molar mass of the fat is 770.5 g/mole. Add all the C, H, and O's (I get C48H98O6) and multiply by the molar mass of each. I obtain the 770.5 grams/mole figure, but would note that a more common fat is actually C3H5(O<u>H</u>(CH2)14(CH3))3 and not C3H5(O<u>O</u>(CH2)14(CH3))3.

Assuming C3H5(OO(CH2)14(CH3))3 is the correct structure, 1000g would mean 1000g/(770.5 g/mole) = 1.298 moles, or 1.30 moles to 2 sig figs.

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How many moles of na2co3 are necessary to reach stoichiometric quantities with cacl2

lbvjy [14]

0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary to reach stoichiometric quantities with cacl2.

<h3>Explanation:</h3>

Based on the reaction

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

1 mole of CaCl₂ reacts per mole of Na₂CO₃

we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g

We must calculate the moles of CaCl2•2H2O using its molar mass (147.0146g/mol) in order to answer this issue.
These moles, which are equal to moles of CaCl2 and moles of Na2CO3, are required to obtain stoichiometric amounts.
Then, we must use the molar mass of Na2CO3 (105.99g/mol) to determine the mass:

<h3>Moles CaCl₂.2H₂O:</h3>

1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂

Moles Na₂CO₃:

0.0102 moles Na₂CO₃

Mass Na₂CO₃:

0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present

Therefore, we can conclude that 0.0102 moles Na₂CO₃ is necessary.to reach stoichiometric quantities with cacl2.

To learn more about stoichiometric quantities visit:

<h3>brainly.com/question/28174111</h3>

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7 0

2 years ago

All the elements of a family in the periodic table have what feature in common?a)they all have similar chemical properties.b)the

Vadim26 [7]

<span>Answer: D. They all have the same number of electrons in the electron cloud</span>

5 0

3 years ago

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7. Bananas contain potassium. Which form of potassium is most likely found in bananas or in nature? a. K atom b. K+ cation C. K-

bulgar [2K]

Answer:

B. K+cation

Explanation:

Not all that sure but hope it will help.

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3 years ago

How would adding the catalyst nitrogen monoxide (NO) affect this reaction?

marin [14]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.

This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.

It does not affect the concentration of the reactants.

For the given reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is $SO_3$

Hence, the correct answer is Option A.

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4 years ago

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For the reaction CO+2H2=CH3OH at 700 K, equilibrium concentrations are [H2]=0.072 M, [CO]= 0.020M, and [CH3OH]= 0.030 M. Calcula

bekas [8.4K]

The balanced equation for the reaction is

CO(g) + 2H₂(g) ⇄ CH₃OH(g)

The given concentrations are at equilibrium state. Hence we can use them directly in calculation with the expression for the equilibrium constant, k. expression for k can be written as

k = [CH₃OH(g)] / [CO(g)] [H₂<span>(g) ]²

</span>[H₂<span>]=0.072 M
[CO]= 0.020M
[CH</span>₃OH]= 0.030 M

From substitution,

k = 0.030 M / 0.020 M x (0.072 M)²

k = 289.35 M⁻²

<span>
Hence, equilibrium constant for the given reaction at 700 K is 289.35 M</span>⁻².

3 0

3 years ago