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natita [175]
3 years ago
6

Calculate the concentration of h3o⁺ in a solution that contains 5.5 × 10-5 m oh⁻ at 25°c. Identify the solution as acidic

Chemistry
1 answer:
Andreas93 [3]3 years ago
7 0

Answer: [H_3O^+]=1.6\times 10^{-10}M , the solution is basic

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.

pH=-\log [H_3O^+]

pOH=-\log[OH^-]

Putting in the values:

pOH=-\log[5.5\times 10^{-5}]

pOH=4.2

pH+pOH=14

pH=(14-pOH)=(14-4.2)=9.8

9.8=-\log [H_3O^+]

[H_3O^+]=1.6\times 10^{-10}M

As pH is more than 7, the solution is basic

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A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental
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Answer:

the empirical (lowest raios) is

C2H4Cl    

Explanation:

A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental analysis, it was determined that the compound is composed of 24.27% carbon.

What is the empirical formula of this compound?

the compound has ONLY C, H, and Cl

the % Cl  = 100% - 24.27% -4.03% = 71.7%

in 100 gm, there are 71.7 gm Cl, 24.27 gm C, and 4.03 gm H

the number of moles are Cl=71.7/70.91 =1.01= ~ 1

                                          C = 24.27/12.0 = 2.02 =~ 2

                                           H = 403/1.01 = 3.97 =~   4

so   the empirical (lowest raios) is

C2H4Cl      

                                 

                               

3 0
3 years ago
What is the percent yield of water produced when 138 g ethyl alcohol, c2h5oh, is combusted in excess oxygen, if the actual exper
kvasek [131]
Hope this helps you.

5 0
3 years ago
Scientific notation is
Murrr4er [49]

Answer:

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Key words:

1: Scientific

2: Quantities

3: Decimal

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8 0
4 years ago
Which reactant will be in excess, and how many moles of it will be left over?
timofeeve [1]

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Explanation:

5 0
3 years ago
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The pH of a 1.0M solution of butanoic acid HC4H7O2 is measured to be 2.41. Calculate the acid dissociation constant Ka of butano
Lubov Fominskaja [6]

Answer:

Ka = 1.52 E-5

Explanation:

  • CH3-(CH2)2-COOH ↔ CH3(CH2)2COO-  + H3O+

⇒ Ka = [H3O+][CH3)CH2)2COO-] / [CH3(CH2)2COOH]

mass balance:

⇒<em> C</em> CH3(CH2)2COOH = [CH3(CH2)2COO-] + [CH3(CH2)2COOH] = 1.0 M

charge balance:

⇒ [H3O+] = [CH3(CH2)2COO-]

⇒ Ka = [H3O+]²/(1 - [H3O+])

∴ pH = 2.41 = - Log [H3O+]

⇒ [H3O+] = 3.89 E-3 M

⇒ Ka = (3.89 E-3)² / ( 1 - 3.89 E-3 )

⇒ Ka = 1.519 E-5

3 0
3 years ago
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