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mixer [17]
4 years ago
5

The zinc within a copper-plated penny will dissolve in hydrochloric acid if the copper coating is filed down in several spots (s

o that the hydrochloric acid can get to the zinc). The reaction between the acid and the zinc is as follows: 2H+(aq)+Zn(s)→H2(g)+Zn2+(aq). When the zinc in a certain penny dissolves, the total volume of gas collected over water at 25 ∘C was 0.947 L at a total pressure of 740 mmHg. What mass of hydrogen gas is collected?
Chemistry
1 answer:
Levart [38]4 years ago
8 0

<u>Answer:</u> The amount of hydrogen gas collected will be 0.073 g

<u>Explanation:</u>

We are given:

Vapor pressure of water = 23.78 mmHg

Total vapor pressure = 740 mmHg

Vapor pressure of hydrogen gas = Total vapor pressure - Vapor pressure of water = (740 - 23.78) mmHg = 716.22 mmHg

To calculate the amount of hydrogen gas collected, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 716.22 mmHg  

V = Volume of the gas = 0.947 L

T = Temperature of the gas = 25^oC=[25+273]K=298K

R = Gas constant = 62.364\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

716.22mmHg\times 0.947L=n\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{716.22\times 0.947}{62.364\times 298}=0.0365mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of hydrogen gas = 0.0365 moles

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

0.0365mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Mass of hydrogen gas}=(0.0365mol\times 2g/mol)=0.073g

Hence, the amount of hydrogen gas collected will be 0.073 g

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