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Daniel [21]
4 years ago
11

The oxidative phase of the pentose phosphate pathway is___________.

Chemistry
1 answer:
Paraphin [41]4 years ago
6 0

Answer:

C: Produces ribulose-5-phosphate and NADPH for biosynthetic processes.

Explanation:

There are two distinct phases in the pathway. The first is the oxidative phase, in which NADPH is generated, and the second is the non-oxidative synthesis of 5-carbon sugars. For most organisms, the pentose phosphate pathway takes place in the cytosol; in plants, most steps take place in plastids.

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five atoms of hydrogen are reactants in a chemical reaction. how many atoms of hydrogen will be found in the products of that re
Mkey [24]

Answer:

5 atoms of hydrogen will be found in the products

Explanation:

5 atoms of hydrogen will be found in the products becuase the law of conservation of mass states that mass is neither created nor destroyed in chemical reactions.

6 0
3 years ago
How many significant figures<br> are in this number?<br> 43.55
leva [86]

Answer:

4 significant figures

Explanation:

Significant figures are the units/digits within a number that make the number more accurate and precise.

All digits (except for 0) are always significant. Therefore, all the digits in 43.55 are significant. Since there are 4 digits in the given number, there are 4 significant figures.

7 0
2 years ago
Juan inflates a balloon and then releases its end to let the balloon go free as air comes out. The balloon then flies around the
MArishka [77]
Here is the correct option: According to Newton's third law of motion, the balloon is pushed forward as the air is forced out.  Newton's third law of motion states that for every action there is an equal and opposite reaction. This means that in every interaction, there is a pair of force that is acting on the interacting objects, the size of the force on the first object is equal to the size of the force on the second object.
5 0
3 years ago
Read 2 more answers
aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid wat
aleksandr82 [10.1K]

Answer:

Explanation:

HCl    + NaOH     =    NaCl    +     H₂O.

1 mole   1 mole           1 mole          1 mole

6.93  g of hydrochloric acid = 6.93 / 36.5 = .189 mole of HCl

2.4 g of NaOH = 2.4 / 40 =  .06 mole of NaOH

NaOH is in short supply so it is the limiting reagent .

1  mole of NaOH reacts with 1 mole of HCl to give 1 mole of Water

.06 mole of NaOH will react with .06 mole of HCl to give .06 mole of water

Water formed = .06 mole

= .06 x 18 = 1.08 g

= 1.1 g

4 0
3 years ago
If 12.6 grams of iron (III) oxide reacts with 9.65 grams of carbon monoxide to produce 7.23 g of pure iron, what are the theoret
Mariana [72]
The balanced equation is Fe₂O₃ + 3 CO = 2 Fe + 3 CO₂.
Next step is to convert everything to moles.
12.6g Fe₂O₃ x (1 mol Fe₂O₃ / 159.7g Fe₂O₃) = 0.07890 mol Fe₂O₃ 
9.65g CO x (1 mol CO / 28.01g CO) = 0.3445 mol CO
The third step is to determine the limiting and excess reactants.
0.07890 mol Fe₂O₃ x (3 mol CO/1 mol Fe₂O₃) = 0.2367 mol CO
Therefore Fe₂O₃ is the limiting reagent while CO is in excess.

0.07890 mol Fe x (2 mol Fe(s) / 1 mol Fe₂O₃) = 0.1578 mol Fe(s) 
0.1578 mol Fe x (55.84g Fe / mole Fe) = 8.812g Fe is the theoretical yield
%yield = (7.23g / 8.812g) x 100% = 82.0% is the percent yield
3 0
3 years ago
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