Don’t like the link it’s dangerous and reply to my comment to i can help you :)
I believe your answer would be NaOH.
Hope this helps.
1. Given the following equation: N2 (g) + 3 H2 (g) ↔ 2NH3 (g) ΔH = -92 kJ/mol
a. this reaction is exothermic as ΔH is -ve
b. the equilibrium will shift 2 the left if nitrogen gas is removed
c. the equilibrium shift 2 the right if the temperature is lowered
d. the equilibrium shift 2 the left if ammonia (NH3) is added
e. principle of thermodynamic potential or Gibbs energy is used to answer B-D
Answer:
The PH of the mixture is 4.74
Explanation:
The number of millimoles of acetic acid is calculated using the formula:
No of millimoles= Molarity * Volume( in ml)
= 0.25M * 30ml = 7.5 moles
Number of millimoles of KOH is calculated using:
Number of millimoles = Molarity * Volume ( in ml)
=0.05M * 75ml
= 3.75 moles
The PH of the solution is derived using:
pH = pKa + log [salt] / acid
= ![-log [ 1.8 * 10^5 ] + log [ 3.75 mmoles/ 3.75 mmoles]](https://tex.z-dn.net/?f=%20-log%20%5B%201.8%20%2A%2010%5E5%20%5D%20%2B%20log%20%5B%203.75%20mmoles%2F%203.75%20mmoles%5D%20)
=4.74
Answer:
The correct answer is option C
sadly, you're wrong