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Lina20 [59]
3 years ago
11

Maria examines a mixture that appears to be the same throughout. However, when she looks at a sample using a magnifying lens, sh

e can see small droplets of liquid surrounded by another liquid. Which conclusion best fits her observations? The mixture is a solution because it has the same appearance throughout the sample. The mixture is a suspension because it is composed of two different-appearing substances. The mixture is a heterogeneous mixture because one liquid is dissolved in the other. The mixture is a colloid because two different substances can be seen in a small sample.
Chemistry
2 answers:
garik1379 [7]3 years ago
6 0

Answer is: The mixture is a colloid because two different substances can be seen in a small sample.

Colloid is microscopically insoluble particles that are suspended throughout another substance. For example whipped cream and gelatin.

For example, in the presence of an emulsifying agent, a mixture of oil and water becomes a colloidal dispersion.

Colloidal dispersion otherwise colloid is a system, in which discrete particles, droplets or bubbles of a dispersed phase (in this case oil), whose size at least in one dimension is in the range from 1 to 1000 nm are distributed in the other, usually continuous phase - dispersion medium (in this case water) differing from the dispersed phase in composition or state of aggregation.

Stella [2.4K]3 years ago
5 0
<span>The mixture is a colloid because two different substances can be seen in a small sample.</span>
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omeli [17]

Answer:

All three are present

Explanation:

Addition of 6 M HCl would form precipitates of all the three cations, since the chlorides of these cations are insoluble: AgCl (s), PbCl_2 (s), Hg_2Cl_2 (s).

  • Firstly, the solid produced is partially soluble in hot water. Remember that out of all the three solids, lead(II) choride is the most soluble. It would easily completely dissolve in hot water. This is how we separate it from the remaining precipitate. Therefore, we know that we have lead(II) cations present, as the two remaining chlorides are insoluble even at high temperatures.
  • Secondly, addition of liquid ammonia would form a precipitate with silver: AgCl (s) + 2 NH_3 (aq) + H_2O (l)\rightarrow [Ag(NH_3)_2]OH (s) + HCl (aq); Silver hydroxide at higher temperatures decomposes into black silver oxide: 2 [Ag(NH_3)_2]OH (s)\rightarrow Ag_2O (s) + H_2O (l) + 4 NH_3 (g).
  • Thirdly, we also know we have Hg_2^{2+} in the mixture, since addition of potassium chromate produces a yellow precipitate: Hg_2^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow Hg_2CrO_4 (s). The latter precipitate is yellow.
3 0
3 years ago
What is the electron configuration of Zn2+
boyakko [2]
. 1s2 2s2 2p6 3s2 3p6 3d10 One point is earned for the correct configuration.
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3 years ago
In which orbitals would the valence electrons for selenium (Se) be placed?
meriva

Answer:

Valence electrons of selenium will be placed in s and p-orbitals.

Explanation:

Hope this helps.

3 0
3 years ago
Calculate the maximum KE and velocity of an electron from zinc by a 275nm photon
Dmitry [639]

Answer:

Kinetic energy: 6.024*10^{-20}

Velocity: 3.64*10^{5}

Explanation:

From the equations of the photo-electric effect,

We know:

hv=hv_0+K.E

Where,

1.h is the Planck's constant which is 6.626*10^{-34}

2.v,v_0 are the frequency of light emitted and threshold frequencies respectively.

3.K.E is the kinetic energy of the electrons emitted.

By fact, we come to know that the threshold frequency of Zn is 300nm

And also v=\frac{c}{d}

Where ,

1. c is the speed of light =3*10^8

2.d is the wavelength.

Thus,

\frac{hc}{d}=\frac{hc}{d_0}+K.E\\K.E=\frac{hc}{d}-\frac{hc}{d_0}\\K.E=hc*(\frac{1}{d}-\frac{1}{d_0})\\K.E=6.626*10^{-34}*3*10^8*(\frac{1}{275*10^{-9}}-\frac{1}{300*10^{-9}})\\K.E=6.024*10^{-20}kgm^2s^{-2}

Now to find velocity:

K.E=\frac{1}{2}mv^2\\v^2=1.324*10^{11}\\v=3.64*10^5

8 0
3 years ago
A gas has a volume of 4 L at a temperature of -33°C. if the temperature is increased to 27°C in the pressure remains constant wh
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Answer:

5L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

4 0
3 years ago
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