15 ppm
1.5 × 10-2 ppm
1.5 × 104 ppm
3.1 ppm
1.5 × 10-2 ppm
Answer:
Imine can be isolated from the reaction mixture as water is continuously removed from the reaction chamber
Explanation:
In this reaction, a non -aqueous solvent is not used (not mentioned in the question). Thus, we can say that there is continuous removal water under suitable reacting conditions and hence the imine formed is left behind.
To answer this question, we need to convert the given number of moles of the compound copper (II) cyanide to grams by multiplying the compound's molar mass. The molar mass of copper (II) cyanide is 115.55 g/mol. Multiply 4 by this number, the answer is 462.2 grams.
Answer:
Fixed volume is the property of liquid and solid which means that the volume of both solid and liquid remain fixed or constant under fixed temperature and pressure.
Elastic Volumes makes it easy to dynamically increase capacity, tune performance, and change the type of any new or existing current generation volume with no downtime or performance impact.
~ Komaljeet ( I hope this helps.) ♥
Answer:
Explanation:
Initial burette reading = 1.81 mL
final burette reading = 39.7 mL
volume of NaOH used = 39.7 - 1.81 = 37.89 mL .
37.89 mL of .1029 M NaOH is used to neutralise triprotic acid
No of moles contained by 37.89 mL of .1029 M NaOH
= .03789 x .1029 moles
= 3.89 x 10⁻³ moles
Since acid is triprotic , its equivalent weight = molecular weight / 3
No of moles of triprotic acid = 3.89 x 10⁻³ / 3
= 1.30 x 10⁻³ moles .
