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n200080 [17]
2 years ago
13

Which of the following aqueous solutions are good buffer systems?

Chemistry
1 answer:
garri49 [273]2 years ago
8 0

The following aqueous solutions represents good buffer systems:

  • 0.22 M acetic acid + 0.15 M potassium acetate
  • 0.29 M ammonium nitrate + 0.32 M ammonia

<h3>What is a buffer?</h3>

A buffer is a solution used to stabilize the pH (acidity) of a liquid.

A good buffer system is generally known to contain close or equal concentrations of a weak acid and its conjugate base.

Based on the above explanation, the following represents a good buffer system as they are between their weak acid and conjugate base:

  • 0.22 M acetic acid + 0.15 M potassium acetate
  • 0.29 M ammonium nitrate + 0.32 M ammonia

Learn more about buffer at: brainly.com/question/22821585

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3 years ago
If 57.3 l of 0.497 m koh is required to completely neutralize 39.5 l of a CH3COOH solution. What is the molarity of the acetic a
bearhunter [10]

The molarity of the solution will be 0.72 m.

The majority of reactions take place in solutions, making it crucial to comprehend how the substance's concentration is expressed in a solution when it is present. The number of chemicals in a solution can be stated in a variety of ways, including.

The symbol for it is M, and it serves as one of the most often used concentration units. Its definition states how many moles of solute there are in a liter of solution.

Given data:

V_{1} =57.3 L\\V_{2} = 39.5 L\\M_{1} = 0.497 m\\\\M_{2} = ?

Molarity can be determined by the formula:

M_{1} V_{1} = M_{2} V_{2}

where, M is molarity and V is volume.

Put the value of given data in above equation.

57.3 × 0.497 m = M × 39.5 L

M = 0.72 m

Therefore, the molarity of the solution will be 0.72 m

To know more about molarity

brainly.com/question/18648803

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2 years ago
Ceres is a dwarf planet located in the main asteroid belt. Which statement about Ceres is false
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Read 2 more answers
Calculate the pH of a solution that is 0.235M benzoic acid and 0.130M sodium benzoate, a salt whose anion is the conjugate base
lesantik [10]

Hello!

We have the following data:

ps: we apply Ka in benzoic acid to the solution.

[acid] = 0.235 M (mol/L)

[salt] = 0.130 M (mol/L)

pKa (acetic acid buffer) =?

pH of a buffer =?

Let us first find pKa of benzoic acid, knowing that Ka (benzoic acid) = 6.20*10^{-5}

So:

pKa = - log\:(Ka)

pKa = - log\:(6.20*10^{-5})

pKa = 5 - log\:6.20

pKa = 5 - 0.79

\boxed{pKa = 4.21}

Now, using the abovementioned data for the pH formula of a buffer solution or (Henderson-Hasselbalch equation), we have:

pH = pKa + log\:\dfrac{[salt]}{[acid]}

pH = 4.21 + log\:\dfrac{0.130}{0.235}

pH = 4.21 + log\:0.55

pH = 4.21 + (-0.26)

pH = 4.21 - 0.26

\boxed{\boxed{pH = 3.95}}\end{array}}\qquad\checkmark

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR! =)

8 0
3 years ago
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