All categories

1 year ago

Which of the following aqueous solutions are good buffer systems?

Chemistry

1 answer:

garri49 [273]1 year ago

8 0

The following aqueous solutions represents good buffer systems:

0.22 M acetic acid + 0.15 M potassium acetate
0.29 M ammonium nitrate + 0.32 M ammonia

<h3>What is a buffer?</h3>

A buffer is a solution used to stabilize the pH (acidity) of a liquid.

A good buffer system is generally known to contain close or equal concentrations of a weak acid and its conjugate base.

Based on the above explanation, the following represents a good buffer system as they are between their weak acid and conjugate base:

0.22 M acetic acid + 0.15 M potassium acetate
0.29 M ammonium nitrate + 0.32 M ammonia

Learn more about buffer at: brainly.com/question/22821585

#SPJ1

You might be interested in

Write the first and second ionization equations for H2SeO3 please.

IRISSAK [1]

As a diprotic acid, the H₂SeO₃ can ionize by step. First step is H₂SeO₃ =(reversible reaction) H⁺ + HSeO₃⁻. And second step is HSeO₃⁻ =(reversible reaction) H⁺ +SeO₃ ²⁻.

3 0

2 years ago

This is another word for microorganism.

nadezda [96]

Answer:

The another word for microorganism is microbe

7 0

3 years ago

Read 2 more answers

When you heat a liquid, the molecules spread farther apart and the liquid expands, and when you cool a liquid, the molecules get

ale4655 [162]

Answer:

the water is diffrent because it is now a gas not a liquid

Explanation:

4 0

3 years ago

Read 2 more answers

What is the mass in milligrams of 4.30 moles of sodium?use âeâ for âÃ10" and use significant figures?

Elis [28]

First, calculate the mass of sodium in g with the help of molar mass and number of moles.

Number of moles = $\frac{given mass in g}{molar mass}$ (1)

Molar mass of sodium = $23 .0 g/mol$

Substitute the given value of number of moles and molar mass of sodium in formula (1)

$4.30 moles = \frac{given mass in g}{23.0 g/mol}$ (1)

$4.30 moles\times 23.0 g/mol = mass in g$ (1)

mass of sodium in g = $98.9 g$

Now, according to conversion factor, 1 g = 1000 mg

So, $98.9 g$ of sodium = $98.9 \times 1000 mg$

= $98900 mg$ of sodium

Thus, mass of sodium in mg = $9.89 \times 10^{4} mg$

8 0

3 years ago

Choose all the answers that apply.

Rashid [163]

B:Creates energy through fusion reactions

7 0

3 years ago

Read 2 more answers