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1 year ago

Which of the following aqueous solutions are good buffer systems?

Chemistry

1 answer:

garri49 [273]1 year ago

8 0

The following aqueous solutions represents good buffer systems:

0.22 M acetic acid + 0.15 M potassium acetate
0.29 M ammonium nitrate + 0.32 M ammonia

<h3>What is a buffer?</h3>

A buffer is a solution used to stabilize the pH (acidity) of a liquid.

A good buffer system is generally known to contain close or equal concentrations of a weak acid and its conjugate base.

Based on the above explanation, the following represents a good buffer system as they are between their weak acid and conjugate base:

0.22 M acetic acid + 0.15 M potassium acetate
0.29 M ammonium nitrate + 0.32 M ammonia

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A solution was prepared by mixing 50.0 g

frez [133]

Answer:

4.78 %.

Explanation:

mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.

mass % = (mass of solute/mass of solution) x 100.

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

∴ mass % = (mass of solute/mass of solution) x 100 = (50.0 g/1047.0 g) x 100 = 4.776 % ≅ 4.78 %.

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3 years ago

When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _

olya-2409 [2.1K]

Balancing redox reactions:

Oxygen should be balanced by adding $H_{2}O$ as needed, while hydrogen should be balanced by adding $H^{+}$ .

What is a redox reaction?

Redox reactions, also known as oxidation-reduction reactions, involve the simultaneous oxidation and reduction of two different reactants.

The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.

By changing the coefficients and adding $H_{2}O$ , $H^{+}$ , and $e^{-}$ in that order, each reaction is brought into equilibrium:

By putting the right number of water ( $H_{2}O$ ) molecules on the other side of the equation, the oxygen atoms are brought into balance.
By adding $H^{+}$ ions to the opposing side of the equation, one can balance the hydrogen atoms (including those added in step 2 to balance the oxygen atom).
Total the fees for each side. Add enough electrons ( $e^{-}$ ) to the more positive side to make them equal. (As a general rule, $e^{-}$ and $H^{+}$ are nearly always on the same side.)
The $e^{-}$ on either side must be made equal; if not, they must be multiplied by the lowest common multiple (LCM) in order to make them equal.
One balanced equation is created by adding the two half-equations and canceling out the electrons. Additionally, common terms should be eliminated.
Now that the equation has been verified, it can be balanced.

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2 years ago

What is the frequency of a radio wave with a wavelength of 578.0m

Radda [10]

Answer:

0.0017 Hz

Explanation:

the solution is in the photo

4 0

3 years ago

Help Asap plz!!!!!!!!

faust18 [17]

I think C. Mutualism.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Determine whether each substance will sink or float in corn syrup, which has a density of 1.36 g/cm3. Write “sink” or “float” in

kondor19780726 [428]

Answer:

Here's what I get

Explanation:

A substance with ρ < 1.36 g/cm⁻³ will float on corn syrup.

A substance with ρ > 1.36 g/cm⁻³ will sink in corn syrup

$\begin{array}{rrr}\textbf{Substance} & \mathbf{\rho/g\cdot \textbf{cm}^{-3}}& \textbf{Sink/Float}\\\text{Gasoline} & 0.75 & \text{Float}\\\text{Water} & 1.00 & \text{Float}\\\text{Corn syrup} & 1.36 & -\\\text{Honey} & 1.42 & \text{Sink}\\\text{Titanium} & 4.54 & \text{Sink}\\\end{array}$

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2 years ago

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