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zysi [14]
3 years ago
14

How many grams are there in 4 moles of cu(cn)2?

Chemistry
2 answers:
Nina [5.8K]3 years ago
8 0
To answer this question, we need to convert the given number of moles of the compound copper (II) cyanide to grams by multiplying the compound's molar mass. The molar mass of copper (II) cyanide is 115.55 g/mol. Multiply 4 by this number, the answer is 462.2 grams.
Liula [17]3 years ago
8 0

<u>Answer:</u> The mass of given amount of copper (II) cyanide is 462.4 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Moles of copper (II) cyanide = 4 moles

Molar mass of copper (II) cyanide = 115.6 g/mol

Putting values in above equation, we get:

4mol=\frac{\text{Mass of }Cu(CN)_2}{115.6g/mol}\\\\\text{Mass of }Cu(CN)_2=(4mol\times 115.6g/mol)=462.4g

Hence, the mass of given amount of copper (II) cyanide is 462.4 g

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In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalliza
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Sample means for solutions 1 and 2 are 19.27 and 10.32 respectively

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The total for answer 1 is given by:

9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7

The sample size is 10 and provides us with

192.7/10 = 19.27

For solution 2, the sum is given by:

10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2

The sample size is 10, this gives us

103.2/10 = 10.32

The total for answer 2 is given by:

10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2

The sample size is 10 and provides us with

103.2/10 = 10.32

Learn more about semiconductor manufacturing here brainly.com/question/22779437

#SPJ4.

In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalization. The etch rate is an important characteristic in this process and is known to follow a normal distribution. Two different etching solutions have been compared, using two random samples of 10 wafers for each solution. Assume the variances are equal. The etch rates are as follows (in mils per minute): Solution 1 Solution 2 9.7 10.6 10.5 10.3 9.4 10.3 10.6 10.2 9.3 10.0 10.7 10.7 9.6 10.3 10.4 10.4 10.2 10.1 10.5 10.3 Calculate sample means of solution 1 and solution 2

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