Question

3.51e23 atoms Fe= g Fe

Answer 1

Answer:

Mass of Fe = 32.55 g

Explanation:

Molar Mass of Fe atom = 55.845 g/mol

It means,

1 mole of Fe contains = 55.845 g ..............(1)

From mole concept,

1 mole of Fe contain = $6.022\times 10^{23}$ atom ..........(2)

Replace 1 mole in equation (2) by 55.845 g , it become :

55.845 g of Fe contain = $6.022\times 10^{23}$ atoms

Reverse the equation now

$6.022\times 10^{23}$ atoms of Fe contain  =55.845 g

1 atom of Fe contain = $\frac{55.845}{6.022\times 10^{23}}$ g

$3.51\times 10^{23}$ atom contain =

$\frac{55.845}{6.022\times 10^{23}}\times 3.51\times 10^{23}$

on calculation,

$3.51\times 10^{23}$ atom contain = 32.55 g of Fe

Mass of Fe = 32.55 g