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uranmaximum [27]
3 years ago
7

Select the statement that describes the relationship between the rate of a reaction and the length of time needed to produce a g

iven quantity of a product of the reaction.
There is no relationship between the rate of the reaction and the time required to produce a given amount of product.

The time required to produce a given quantity of a product is inversely proportional to the rate of the reaction. For a reaction that runs twice as fast, the given quantity of product will be produced in half the time.

There is a relationship between the rate of a reaction and the time required to produce a given quantity of a product. It is not possible to know what that relationship is without running experiments.

The time required to produce a given quantity of a product is directly proportional to the rate of the reaction. For a reaction that runs twice as fast, the given quantity of product will be produced in twice the time.
Chemistry
2 answers:
Naily [24]3 years ago
7 0

Answer:

The time required to produce a given quantity of a product is inversely proportional to the rate of the reaction. For a reaction that runs twice as fast, the given quantity of product will be produced in half of the time.

Explanation:

As the reaction progresses to form products, the number of successful collision decreases with increase in time and as rate increases with an increase in the collision between reactants,  then time decreases.

With an increase in the system temperature, concentration, surface area and the presence of catalyst, the reaction rate increase alongside decreasing the time needed to turn reactants to products.

For instance, the presence of a catalyst in a reaction speeds up or increases the reaction rate thereby providing an alternative route or pathway to the products thereby decreasing the time of product yield and lowering the activation energy of the reaction.

Therefore as the rate increases, the time needed to convert reactants to products decreases

slava [35]3 years ago
7 0
I really don’t know
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6 0
3 years ago
Calculate the pH for each of the following cases in the titration of 25.0 mL of 0.150 M sodium hydroxide with 0.150 M HBr(aq). (
Taya2010 [7]

Answer:

a) pH = 13.176

b) pH = 13

c) pH = 12.574

d) pH = 7.0

e) pH = 1.46

f) pH = 1.21

Explanation:

HBr + NaOH ↔ NaBr + H2O

∴ equivalent point:

⇒ mol acid = mol base

⇒ (Va)*(0.150mol/L) = (0.025L)*(0.150mol/L)

⇒ Va = 0.025 L

a) before addition acid:

  • NaOH → Na+  + OH-

⇒ <em>C </em>NaOH = 0.150 M

⇒ [ OH- ] = 0.150 M

⇒ pOH = - Log ( 0.150 )

⇒ pOH = 0.824

⇒ pH = 14 - pOH

⇒ pH = 13.176

b) after addition 5mL HBr:

⇒ <em>C </em>NaOH = (( 0.025)*(0.150) - (0.005)*(0.150)) / (0.025 + 0.005) = 0.1 M

⇒ <em>C </em>HBr = (0.005)*(0.150) / ( 0.03 ) = 0.025 M

⇒ [ OH- ] = 0.1 M

⇒ pOH = 1

⇒ pH = 13

c) after addition 15mL HBr:

⇒ <em>C </em>NaOH = ((0.025)*(0.150) - (0.015)*(0.150 ))/(0.04) = 0.0375 M

⇒ <em>C </em>HBr = ((0.015)*(0.150))/(0.04) = 0.0563 M

⇒ [ OH- ] = 0.0375 M

⇒ pOH = 1.426

⇒ pH = 12.574

d) after addition 25mL HBr:

equivalent point:

⇒ [ OH- ] = [ H3O+ ]

⇒ Kw = 1 E-14 = [ H3O+ ] * [ OH- ] = [ H3O+ ]²

⇒ [ H3O+ ] = 1 E-7

⇒ pH = 7.0

d) after addition 40mL HBr:

⇒ <em>C</em> HBr = ((0.04)*(0.150) - (0.025)*(0.150)) / (0.04 + 0.025) = 0.035 M

⇒ [ H3O+ ] = 0.035 M

⇒ pH = 1.46

d) after addition 60mL HBr:

⇒ <em>C</em> HBr = ((0.06)*(0.150) - (0.025)*(0.150)) / (0.06+0.025) = 0.062 M

⇒ [ H3O+ ] = 0.062 M

⇒ pH = 1.21

8 0
4 years ago
Read 2 more answers
Given the following equation,, how many moles of water will be produced when 12 moles of ethane (C2H6) are burned?
VARVARA [1.3K]

Answer: 36 mol H2O (l)

Explanation:

Let's use stoichiometry to solve this problem.

12 mol C2H6 * (6 mol H2O / 2 mol C2H6) = 36 mol H2O

Hope this helps!

6 0
3 years ago
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